Answer: D
Explanation: Bacteria thrives in warm and moist environments.
<em>The cathode is Y</em>
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Further explanation</em></h3>
Electrolysis uses electrical energy to carry out redox reactions that are not spontaneous.
The ions in the solution flowing electrically will move towards to opposite charge of the electrode
The electrolysis material is an electrolyte which can be a solution or a melt.
In positive pole electrolysis cells - the anode is the site of the oxidation reaction, while the negative pole - the cathode is the reduction reaction site.
The result of the reaction in the anode is based on a substance that easily oxidized while the reaction in the cathode is based on a substance that easily reduced.
Electrons (electricity) enter an electrolysis cell through the negative pole (cathode)
The negative ion from the solution will move towards the positive electrode and release the electrons around the positive electrode (oxidation) and the electrons flow to the negative pole
Whereas around the negative electrode, there is electron binding and a reduction reaction occurs
So if we see the picture the cathode is Y
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Learn more</em></h3><h3><em>
reaction related to electrochemistry brainly.com/question/3461108</em></h3>
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Answer details </em></h3>
Grade: Senior High School
Subject: Chemistry
Chapter: Electrochemistry
Keywords: cathode, anode, oxidation, reduction, negative pole, electrode
Answer:
Relative volume of ether to water that should be used for the extraction = 1.205
Explanation:
The extraction/distribution coefficient of an arbitrary solvent to water for a given substance is expressed as the mass concentration of the substance in the arbitrary solvent (C₁) divided by the mass concentration of the substance in water (C₂).
K = (C₁/C₂)
Let the initial mass of the organic substance X in water be 1 g (it could be any mass basically, it is just to select a right basis, since we are basically working with percentages here).
If 94% of the organic substance X is extracted by ether in a single extraction, 0.94 g ends up in ether and 0.06 g of the organic substance X that remains in water.
Let the volume of ether required be x mL.
Let the volume of water required be y mL.
Relative volume of ether to water that should be used for the extraction = (x/y)
Mass concentration of the organic substance X in ether = (0.94/x)
Mass concentration of organic substance X in water = (0.06/y)
The distribution coefficient , Ko (Cether / C water), for an organic substance X at room temperature is 13.
13 = (0.94/x) ÷ (0.06/y)
13 = (0.94/x) × (y/0.06)
13 = (15.667y/x)
(x/y) = (15.667/13) = 1.205
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