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DerKrebs [107]
3 years ago
15

Which of these four contain an ionic bond, H2O, CO, P2O5, or AlCl3? i answered earlier and I was wrong.

Chemistry
1 answer:
bazaltina [42]3 years ago
6 0
<span>I would say D AlCl3. covalent bonding is when 2 or more elements share electrons (usually when nonmetals bond with nonmetals) ionic bonding is when one element steals another's electrons (usually when nonmetals bond with metals)</span>
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A. A solid forms, and there is a change of color.

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The reaction between zinc (Zn) and hydrogen chloride (HCl) produces zinc chloride (ZnCl), hydrogen (H2) gas, and heat. If more h
andrew-mc [135]

 If more   heat  is removed from the reaction the rate of reaction change as below to counter the action

The rate of the  <em>forward reaction increase</em> and produces more   <em>zinc chloride</em>


<u><em>      explanation</em></u>

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6 0
3 years ago
A liquid has an empirical formula CCl2, and a boiling point of 1 21 oC. When vapourised, the gaseous compound has a density of 4
Darya [45]

Based on the data given, the molar mass of the gas is 165.5 g/mol while the molecular weight of the gas is 165.5 amu

<h3>How can molar mass of a gas be obtained from density, temperature and pressure?</h3>

The molar mass of a gas can be obtained from density, temperature and pressure using the formula below:

  • molar mass = density × molar gas constant × temperature/pressure

Molar gas constant, R = R = 0.082 L.atm/mol/K.

Temperature = 150 °C = 423 K

Pressure = 785 torr = 1.033 atm

density = 4.93 g/L

molar mass of gas = 4.93 × 0.082 × 423/1.033

molar mass of gas = 165.5 g/mol

Then, molecular weight of the gas = 165.5 amu

Therefore, the molar mass of the gas is 165.5 g/mol while the molecular weight of the gas is 165.5 amu

Learn more about molar mass of a gas at: brainly.com/question/26215522

6 0
2 years ago
Determine the vapor pressure (atm) of rubbing alcohol (isopropanol) at 20.0 °C. The normal boiling point of isopropanol is 82.3
jeyben [28]
Here we apply the Clausius-Clapeyron equation:
ln(P₁/P₂) = ΔH/R x (1/T₂ - 1/T₁)

The normal vapor pressure is 4.24 kPa (P₁)
The boiling point at this pressure is 293 K (P₂)
The heat of vaporization is 39.9 kJ/mol (ΔH)
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ln(4.24/P₂) = 39.9/0.008314 x (1/355.3 - 1/293)
P₂ = 101.2 kPa
8 0
3 years ago
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