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Gennadij [26K]
3 years ago
7

During several practice runs you stand at the end of a diving board and launch the basketball horizontally from a position 4.50

m above the water. If the average landing spot is 6.25 m horizontally from your initial position, what is the average launch speed?

Physics
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

6.52m/s

Explanation:

Hello!

To solve this problem follow the steps below, the complete procedure is in the attached image

1. draw a complete outline of the problem involving forces and geometries

2. Find the time that elapses from when the ball is thrown until it hits the water, this is achieved using the kinematic equation for constant acceleration and zero vertical initial velocity.

3. taking into account that the ball is launched horizontally, and that there is no horizontal acceleration, the only thing we must do is find the speed by dividing the distance traveled horizontally and dividing it by time

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A spring on a horizontal surface can be stretched and held 0.2 m from its equilibrium position with a force of 16 N. a. How much
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Answer:

a   W_{3.5} = 490 \  J

b  W_{2.5} =  250 \  J

Explanation:

Generally the force constant is mathematically represented as

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substituting values given in the question

=>   k  = \frac{16}{0.2}

=>   k  =  80 \ N /m

Generally the workdone  in stretching the spring 3.5 m is mathematically represented as

       W_{3.5} =  \frac{1}{2}  *  k  *  (3.5)^2

=>     W_{3.5} =  \frac{1}{2}  *  80  *  (3.5)^2

=>    W_{3.5} = 490 \  J

Generally the workdone  in compressing the spring 2.5 m is mathematically represented as

        W_{2.5} =  \frac{1}{2}  *  k  *  (2.5)^2

=>      W_{2.5} =  \frac{1}{2}  *  80 *  (2.5)^2

=>       W_{2.5} =  250 \  J

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Answer:

T = 40.501\,^{\textdegree}C

Explanation:

The interaction of the piece of copper and water means that the first one need to transfer heat in order to reach a thermal equilibrium with water. Then:

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After a quick substitution, the expanded expression is:

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