During several practice runs you stand at the end of a diving board and launch the basketball horizontally from a position 4.50
m above the water. If the average landing spot is 6.25 m horizontally from your initial position, what is the average launch speed?
1 answer:
Answer:
6.52m/s
Explanation:
Hello!
To solve this problem follow the steps below, the complete procedure is in the attached image
1. draw a complete outline of the problem involving forces and geometries
2. Find the time that elapses from when the ball is thrown until it hits the water, this is achieved using the kinematic equation for constant acceleration and zero vertical initial velocity.
3. taking into account that the ball is launched horizontally, and that there is no horizontal acceleration, the only thing we must do is find the speed by dividing the distance traveled horizontally and dividing it by time
You might be interested in
Answer:
ee that the lens with the shortest focal length has a smaller object
Explanation:
For this exercise we use the constructor equation or Gaussian equation
where f is the focal length, p and q are the distance to the object and the image respectively.
Magnification a lens system is
m = = -
h ’= -\frac{h q}{p}
In the exercise give the value of the height of the object h = 0.50cm and the position of the object p =∞
Let's calculate the distance to the image for each lens
f = 6.0 cm
as they indicate that the light fills the entire lens, this indicates that the object is at infinity, remember that the light of the laser rays is almost parallel, therefore p = inf
q = f = 6.0 cm
for the lens of f = 12.0 cm q = 12.0 cn
to find the size of the image we use
h ’= h q / p
where p has a high value and is the same for all systems
h ’= h / p q
Thus
f = 6 cm h ’= fo 6 cm
f = 12 cm h ’= fo 12 cm
therefore we see that the lens with the shortest focal length has a smaller object
Answer:
undergoes a transition to a quantum state of lower energy
Explanation:
When electrons in an atom move to another quantum state, they emit/absorb a photon according to the following:
- If the electron is moving to a higher energy state, it absorbs a photon (because it needs energy to move to a higher energy level, so it must absorb the energy of the photon)
- if the electron is moving to a lower energy state, it emits a photon (because it releases the excess energy)
In particular, the energy of the absorbed/emitted photon is exactly equal to the difference in energy between the two levels of the electron transition: