4. A plane accelerates down a runway due to the constant resultant force of

Physics

1 answer:

Doss [256]1 year ago

4 0

Answer:

See below

Explanation:

Net force acting on the plane after overcoming frictional forces is

2.7 x 10^6 - 6.8 x 10^4 - 8.5 x 10^5 = 1 782 000 N

Work = F x d

= 1 782 000 x 1400 m = 2.5 x 10^9 J or 2.5 x 10^6 kJ

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