Question

4. A plane accelerates down a runway due to the constant resultant force of

Answer 1

Answer:

See below

Explanation:

Net force acting on the plane after overcoming frictional forces is

2.7 x 10^6   -  6.8 x 10^4   -  8.5 x 10^5 = 1 782 000 N

Work = F x d

        = 1 782 000 x 1400 m = 2.5 x 10^9   J       or  2.5 x 10^6  kJ