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NeTakaya
4 years ago
6

Can Someone please help me solve tus 8x + 7 > -41

Mathematics
1 answer:
Y_Kistochka [10]4 years ago
7 0

x > - 6

given 8x + 7 > - 41 ( subtract 7 from both sides )

8x > - 48 ( divide both sides by 8 )

x > - 6

x ∈ (- 6, ∞ ) ← in interval notation


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Jeff gave 1/4 of a sum of money to his wife. Then he divided the remainder equally among his 4 children.
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Answer:

A) The fraction of sum of money did each child receive is \frac{3 x}{16}

B) The sum of money did Jeff have $ 3200

Step-by-step explanation:

Given as :

Let The sum of money did Jeff have = $ x

The fraction of money did Jeff's wife get = \frac{1}{4} of $ x

The remaining money Jeff will have = $ x - \frac{1}{4} of $ x

I.e The remaining money Jeff will have = \frac{4 x - x}{4}

                                                                = \frac{3 x}{4}

A ) The remaining amount of money is divided equally among 4 children

So, The fraction of sum of money did each child receive = \frac{\frac{3 x}{4}}{4}

I.e The fraction of sum of money did each child receive =  \frac{3 x}{16}

B ) If each child will receive $ 600

∴,  \frac{3 x}{16} = $ 600

Or, 3 x = $ 600 × 16

Or, 3 x = $ 9600

∴    x = \frac{9600}{3}

I.e  x = $ 3200

So, The sum of money did Jeff have $ 3200  

Hence ,

A) The fraction of sum of money did each child receive is \frac{3 x}{16}

B) The sum of money did Jeff have $ 3200   Answer

8 0
3 years ago
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