27. How much energy is required to change 150.0 g of water from 10.0°C to 45.0°C? (Cwater =
1 answer:
Answer:
The answer to your question is letter C. 21900.3. My result was 21945 J, letter C is close to this result.
Explanation:
Data
mass = 150 g
temperature 1 = T1 = 10°C
temperature 2 = T2 = 45°C
Cw = 4.18 J/g°C
Formula
Q = mCΔT = mC(T2 - T1)
Substitution
Q = (150)(4.18)(45 - 10)
Simplification
Q = (150)(4.18)(35)
Result
Q = 21945 J
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W=(m'/m)·100%
m'=37.2 g
m=48.5 g
w=(37.2/48.5)·100%=76.7%
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Step by step explanation: