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attashe74 [19]
4 years ago
12

The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground

? Given: g = –9.8 meters/second2
Physics
2 answers:
Elodia [21]4 years ago
8 0
We know, s = ut + 1/2gt²
In free-fall, u = 0
so, t = √2s/g

Now, substitute the values, 
t = √2*4 / 9.8   [ -ve sign shows opposite direction only ]
t = √8/ 9.8
t = 0.90 sec

In short, Your Answer would be 0.90 sec

Hope this helps!
GarryVolchara [31]4 years ago
6 0

Answer:

0.90 seconds

Explanation:

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A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
RideAnS [48]

Answer:

Explanation:

Initial kinetic energy of M = 1/2 M vi²

let final velocity be vf

v² = u² + 2a s

vf² =  vi² + 2 (F / M) x D

Kinetic energy

= 1/2 Mvf²

= 1/2 M ( vi² + 2 (F / M) x D

1/2 M vi² + FD

Ratio with initial value

1/2 M  vi² + FD) / 1/2 M  vi²

RK = 1 + FD / 2 M  vi²

4 0
3 years ago
A wave changing shape when passing through an opening is an example of what?
igomit [66]
It is diffraction !!
7 0
4 years ago
Spaceship 1 and spaceship 2 have equal masses of 200 kg. Spaceship 1 has a speed of 0 m/s, and spaceship 2 has a speed of 10 m/s
m_a_m_a [10]

Answer:

2000 kg m/s

Explanation:

The momentum of an object is a vector quantity whose magnitude is given by

p=mv

where

m is the mass of the object

v is the velocity of the object

and its direction is the same as the velocity.

In this problem, we have:

- Spaceship 1 has

m = 200 kg (mass)

v = 0 m/s (zero velocity)

So its momentum is

p_1 =(200)(0)=0

- Spaceship 2 has

m = 200 kg (mass)

v = 10 m/s (velocity)

So its momentum is

p_2=(200)(10)=2000 kg m/s

Therefore, the combined momentum of the two spaceships is

p=p_1+p_2=0+2000=2000 kg m/s

3 0
3 years ago
Fossils are generally found inside of what type of rocks?
dusya [7]

Answer:

C sedimentary rocks is the answer.

Explanation:

8 0
4 years ago
Read 2 more answers
A 0.290 kg block on a vertical spring with a spring constant of 5.00 ✕ 103 N/m is pushed downward, compressing the spring 0.110
True [87]

Answer:

The height at point of release is 10.20 m

Explanation:

Given:

Spring constant : K= 5 x 10 to the 3rd power n/m

compression x = 0.10 m

Mass of block m= 0.250 kg

Here spring potential energy converted into potential energy,

mgh = 1/2 kx to the 2 power

For finding at what height it rise,

0.250 x 9.8 x h = 1/2 x 5 x 10 to the 3 power x (0.10)to the 2 power) - ( g= 9.8 m/8 to the 2 power

h= 10.20

Therefore, the height at point of release is 10.20 m

4 0
3 years ago
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