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viktelen [127]
2 years ago
8

The amount of heat per second conducted from the blood capillaries beneath the skin to the surface is 250 j/s. the energy is tra

nsferred a distance of 2.1 × 10-3 m through a body whose surface area is 1.9 m2. assuming that the thermal conductivity is that of body fat, determine the temperature difference between the capillaries and the surface of the skin.
Physics
1 answer:
marin [14]2 years ago
5 0
Heat flux (i) = k.a.temp variation/d
i = 250 J/s or 250w ; d = 2.1 x 10^-3m ; A = 1.9m^2 ; K (Body Fat) = 0.2W/m.Kelvin ; Temp. Var. (Delta T) = ?

-> 250 = 0.2 x 1.9 x deltaT/2.1 x 10^-3
-> 250 x 2.1 x 10^-3 = 0.38 x deltaT
-> 525 x 10^-3 = 38x10^-2 x deltaT
-> deltaT = 525 x 10^-3/ 38 x 10^-2
-> deltaT = 13.81 x 10^(-3 - (-2))
-> deltaT = 13.81 x 10^-1
-> deltaT = 1.381 K
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To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is

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            If we use Newton's second law

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             a = F / m

let's calculate

              a = 187500/2250

              a = 83.33 m / s²

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