Answer:
Because it is charged with the opposite type of energy to the wall.
The solution would be like this for this specific problem:
4 NaOCl + S2O3{2-} + 2
OH{-} → 2 SO4{2-} + H2O + 4 NaCl
<span>(0.00456 L) x (0.100 mol/L
S2O3{2-}) x (4 mol NaOCl / 1 mol S2O3{2-}) x (100.0 mL / 25 mL) x </span><span>
<span>(74.4422 g NaClO/mol) = 0.54313 g </span></span>
<span>(5.00 mL) x (1.08 g/mL) =
5.40 g solution </span>
(0.54313 g) / (5.40 g) =
0.101 = 10.1%
So, the average percent by mass of NaClO in the
commercial bleach is 10.1%.
Answer:
The internal energy of a system <u>is the sum of the potential and kinetic energies of the components</u>
Explanation:
Internal energy is defined as the sum of two types of energy: kinetic energy and potential energy.
Kinetic energy is defined as the sum of all the kinetic energies that each element has within a system with respect to its center of mass. It is caused by the movement of particles. Meanwhile, the potential energy is the energy that is associated with each of the interactions. Potential energy is associated with the constituents of matter, of the electrostatic energy of each atom that is inside the molecules.
Answer & explanation:
Summary on electrochemical cells and redox reactions:
Electrochemical cells (or batteries) can be defined as devices capable of transforming chemical energy into electrical energy through spontaneous reactions of redox, in which electron transfer occurs.
Redox it is a chemical reaction in which there is the occurrence of oxidation and reduction of atoms of substances (chemical species) present in the process.
<u>Oxidation</u> is the loss of electrons by an atom of a chemical species, while <u>reduction</u> is the gain of electrons by an atom of a chemical species.
Thus, during an oxirreduction reaction, electrons move from the species that loses them towards the species that will receive them. This "movement" results in the formation of an electric current (or electrical energy) as occurs with batteries, for example.
Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:
C1V1 = C2V2
(6.0M)(2.0mL) = C2(500.0mL)
Therefore, the final concentration, C2 = 0.024M.
