Answer:

Explanation:
Hello.
In this case, given the heat of fusion of THF to be 8.5 kJ/mol and freezing at -108.5 °C, for the required mass of 5.9 g, we can compute the entropy as:

Whereas n accounts for the moles which are computed below:

Thus, the entropy turns out:

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Answer:
Aluminum metal
Explanation:
In order to properly answer this or a similar question, we need to know some basic rules about galvanic cells and standard reduction potentials.
First of all, your strategy would be to find a trusted source or the table of standard reduction potentials. You would then need to find the half-equations for aluminum and gold reduction:


Since we have a galvanic cell, the overall reaction is spontaneous. A spontaneous reaction indicates that the overall cell potential should be positive.
Since one half-equation should be an oxidation reaction (oxidation is loss of electrons) and one should be a reduction reaction (reduction is gain of electrons), one of these should be reversed.
Thinking simply, if the overall cell potential would be obtained by adding the two potentials, in order to acquite a positive number in the sum of potentials, we may only reverse the half-equation of aluminum (this would change the sign of E to positive):
Notice that the overall cell potential upon summing is:

Meaning we obey the law of galvanic cells.
Since oxidation is loss of electrons, notice that the loss of electrons takes place in the half-equation of aluminum: solid aluminum electrode loses 3 electrons to become aluminum cation.
Answer:
They are Weaker than a chemical
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corrected by the one in the comment section
Answer:
400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed
Explanation:
Let's assume concentration of brine salt solutions are in %(w/v) unit.
Final mixture has a concentration of 11.2% salt and volume of 1 L or 1000 mL
Hence, amount of salt in final mixture = 
Suppose x mL of 4% salt solution and (1000-x) mL of 16% salt solution need to be mixed to get final mixture
So, amount of salt in x mL of 4% salt solution = 
amount of salt in x mL of 16% salt solution =
Hence, 
or, 
So, 400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed