2. A child observes a caterpillar walking on a window sill. The caterpillar walks 18 cm to the left, then 6 cm to
1 answer:
Answer:
D = 8 cm
Explanation:
It is given that, the caterpillar walks 18 cm to the left, then 6 cm to the right, then 10 cm to the left.
We need to find the displacement of the caterpillar. The attached figure shows the path traveled by the caterpillar. A is the initial position, then it reaches B and finally it reaches C.
Let right side is positive and left is negative. We know that,
Displacement = final position - initial position
= C - A
= -10-(-18)
= 8 cm
Hence, the displacement of the caterpillar is 8 cm.
You might be interested in
Refer to the diagram shown below.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.