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3 years ago

2. A child observes a caterpillar walking on a window sill. The caterpillar walks 18 cm to the left, then 6 cm to

Physics

1 answer:

motikmotik3 years ago

8 0

Answer:

D = 8 cm

Explanation:

It is given that, the caterpillar walks 18 cm to the left, then 6 cm to the right, then 10 cm to the left.

We need to find the displacement of the caterpillar. The attached figure shows the path traveled by the caterpillar. A is the initial position, then it reaches B and finally it reaches C.

Let right side is positive and left is negative. We know that,

Displacement = final position - initial position

= C - A

= -10-(-18)

= 8 cm

Hence, the displacement of the caterpillar is 8 cm.

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A satellite orbits a planet of unknown mass in a circular orbit of radius 2.3 x 104 km. The gravitational force on the satellite

sladkih [1.3K]

Answer:

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Explanation:

From the question we are told that

The radius of the orbit is $r = 2.3 *10^{4} \ km = 2.3 *10^{7} \ m$

The gravitational force is $F_g = 6600 \ N$

The kinetic energy of the satellite is mathematically represented as

$KE = \frac{1}{2} * mv^2$

where v is the speed of the satellite which is mathematically represented as

$v = \sqrt{\frac{G M}{r^2} }$

=> $v^2 = \frac{GM }{r}$

substituting this into the equation

$KE = \frac{ 1}{2} *\frac{GMm}{r}$

Now the gravitational force of the planet is mathematically represented as

$F_g = \frac{GMm}{r^2}$

Where M is the mass of the planet and m is the mass of the satellite

Now looking at the formula for KE we see that we can represent it as

$KE = \frac{ 1}{2} *[\frac{GMm}{r^2}] * r$

=> $KE = \frac{ 1}{2} *F_g * r$

substituting values

$KE = \frac{ 1}{2} *6600 * 2.3*10^{7}$

$KE = 7.59 *10^{10} \ J$

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