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lions [1.4K]
2 years ago
14

Which represents the overall (net) reaction of this mechanism: step 1: H2O2 + I- → H2O + OI- step 2: H2O2 + OI- → H2O + O2 + I-

Note that I- acts as a catalyst in this reaction.
A. 2H2O2 → 2H2O + O2

B. H2O2 → H2 + O2

C. H2O2 + I- → OI- + H2O

D. H2O2 + OI- → H2O + O2 + I-
Chemistry
1 answer:
11111nata11111 [884]2 years ago
4 0

Answer:

A. 2H₂O₂  → 2H₂O + O₂

Explanation:

  • 1. H₂O₂ + I⁻ → H₂O + OI⁻
  • 2. H₂O₂ + OI⁻ → H₂O + O₂ + I⁻

If we <u>make a net sum of both reactions</u>, we're left with:

  • H₂O₂ + I⁻ + H₂O₂ + OI⁻ → H₂O + OI⁻ + H₂O + O₂ + I⁻

Grouping species:

  • 2H₂O₂ + OI⁻ + I⁻ → 2H₂O + OI⁻ + O₂ + I⁻

There is OI⁻ at both sides, so it is eliminated -same goes for the catalyst, I⁻-.

  • 2H₂O₂  → 2H₂O + O₂

Thus the answer is option A.

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Answer:

13mL

Explanation:

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The balanced equation for the reaction. This is given below:

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From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

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Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

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MaVa/MbVb = nA/nB

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