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Arturiano [62]
3 years ago
11

A scientist is working in a lab and accidentally combines two liquids that quickly form a solution. Which process could be used

to separate the two liquids?
Chemistry
1 answer:
PIT_PIT [208]3 years ago
7 0

Answer:

Distillation

Explanation:

The method of distillation can be used to separate the two liquids, if their boiling point is known. The liquid with lower boiling point will be evaporated and its vapours will be captured, while the liquid with higher boiling point will remail in the container in the liquid state.

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If you throw a ball into the air, the force of ________ makes the ball fall back toward Earth.
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Read 2 more answers
Explain Charles law​
kodGreya [7K]

"Charles Law" is the relationship between "volume-temperature" (V ∝ T).

<u>Explanation</u>:  

Charles Law is basically volume-temperature relationship (V ∝ T). French scientist “Jacques Charles” in 1787 studied effect of temperature on the volume of gases at constant pressure, which described how gases manage to expand when heated. Law stated as “At constant pressure, the volume of a given "mass" of a gas decreases or increases by 1/273 of its volume at 0^{\circ} \mathrm{C} for each one degree rise or fall in temperature”. Formula derived from law is as follows: \mathbf{V}_{\mathbf{t}}=\mathbf{V}_{0}[\mathbf{1}+\mathbf{t} / \mathbf{2} 7 \mathbf{3}] here {V}_{0} is volume of given mass of a gas at 0^{\circ} \mathrm{C}, {V}_{t} is its volume at any temperature t^{\circ} \mathrm{C}. Application of Charles law is hot air balloons.

8 0
3 years ago
How man grams of cl2 are consumed to produce 12.0 g of KCl
Korvikt [17]

Answer:

5.71 g

Explanation:

Step 1: Write the balanced equation

2 K + Cl₂ ⇒ 2 KCl

Step 2: Calculate the moles corresponding to 12.0 g of KCl

The molar mass of KCl is 74.55 g/mol.

12.0 g × 1 mol/74.55 g = 0.161 mol

Step 3: Calculate the moles of Cl₂ needed to produce 0.161 moles of KCl

The molar ratio of Cl₂ to KCl is 1:2. The moles of Cl₂ needed are 1/2 × 0.161 mol = 0.0805 mol

Step 4: Calculate the mass corresponding to 0.0805 moles of Cl₂

The molar mass of Cl₂ is 70.91 g/mol.

0.0805 mol × 70.91 g/mol = 5.71 g

8 0
3 years ago
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