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faust18 [17]
3 years ago
6

Your friend, a business major, overhears you talking about chemical energy and food and decides to develop a new super food for

busy students that just don’t have time to cook but want to eat a well-balanced diet for a reasonable price. If your friend wants to design a meal bar that contains a high amount of potential energy that the body could use, how would you recommend they rank the possible atom interactions they could incorporate into the chemical formula? Rank from highest chemical energy to lowest.
Chemistry
1 answer:
RUDIKE [14]3 years ago
7 0

Answer:

The question is incomplete. The response options are as follows:

I. C-O or C=O

II. C-C

III. C-H

IV. O-H

The answer is: IV>III>I>II

Explanation:

V) O-H is a hydrogen bridge. The hydrogen bridge is characterized by being similar to dipole-dipole bonds.

III) C-H is an ionic bond. The ionic bond occurs when they fuse together due to electron transfer.

I) C=O is a covalent bond. The covalent bond happens when two atoms bond together to create a molecule, sharing its electrons that are in its most superficial layer,

II) C-C is covalent bond.

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Explanation:

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Which best describes the future of wind power for providing electricity in the United States?
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2 years ago
How many mL of 0.715 M HCl is required to neutralize 1.25 grams of sodium carbonate? (producing carbonic acid)
jonny [76]

Answer:

34 mL

Explanation:

We'll begin by calculating the number of mole in 1.25 g of sodium carbonate, Na₂CO₃. This can be obtained as follow:

Mass of Na₂CO₃ = 1.25 g

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mole of Na₂CO₃ =?

Mole = mass /molar mass

Mole of Na₂CO₃ = 1.25 / 106

Mole of Na₂CO₃ = 0.012 mole

Next, we shall determine the number of mole HCl needed to react with 0.012 mole of Na₂CO₃.

The equation for the reaction is given below:

Na₂CO₃ + 2HCl —> H₂CO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 2 moles of HCl.

Therefore, 0.012 mole of Na₂CO₃ will react with = 0.012 × 2 = 0.024 mole of HCl.

Next, we shall determine the volume of HCl required for the reaction. This is illustrated:

Mole of HCl = 0.024 mole

Molarity of HCl = 0.715 M

Volume of HCl =?

Molarity = mole /Volume

0.715 = 0.024 / volume of HCl

Cross multiply

0.715 × volume of HCl = 0.024

Divide both side by 0.715

Volume of HCl = 0.024 / 0.715

Volume of HCl = 0.034 L

Finally, we shall convert 0.034 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.034 L = 0.034 L × 1000 mL / 1 L

0.034 L = 34 mL

Therefore, 34 mL of HCl is needed for the reaction.

6 0
3 years ago
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