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gayaneshka [121]
3 years ago
10

Calculate the activation energy (ea in kj/mol for a reaction if the rate constant (k is 2.7 × 10-4 (m−1sec−1 at 600 k and 3.5 ×

10−3 (m−1sec−1 at 650 k.
Chemistry
1 answer:
djyliett [7]3 years ago
6 0
Below are the choices:

a. −166 kJ/mol 
<span>b. 166 kJ/mol </span>
<span>c. 1.64 kJ/mol </span>
<span>d. 1.66 × 10^5 kJ/mol
</span>
To calculate the activation energy of a reaction, we use the Arrhenius equation.  You may want to look it up to see how and why it works.  In the problem you posted, there are two temperatures and two rate constants.  After some rearranging and substitution of the Arrhenius equation, we have Ea = R T1 T2/(T1-T2) ln(k1/k2) = 8.314 J/mol K (600 K)(650 K)/(600 K-650 K) ln(2.7×10^-4 M^−1sec^−1/3.5×10^−3 M−^1sec^−1) = 166145 J/mol = 166 kJ/mol => choice b
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Answer: pure substances.


Explanation:


The given substances are:

  • H₂O₂
  • Li
  • NaCl
  • O₂

All what surrounds us, which has mass and occupies spaces, is matter. There are two kind of matter: pure substances and mixtures.


Pure substances have a uniform and constant composition. On the other hand, mixtures are combinations of two or more pure substances in  any arbitratry ratio.


Pure substances may be elements or compounds. The elements are the substances conmposed by one only kind of atom. In the list of substances given, Li and O₂ are elements: all the atoms in Li are lithium, and all the atoms in O₂ are oxygen atoms.


Compounds are the chemical combination of two or more different kind of atoms. In the given list H₂O₂ and NaCl are compounds. As you see, H₂O₂ contains atoms of hydrogen and oxygen, chemically bonded, in a fixed ratio (2 atoms of hydrogen by 2 atoms of oxygen). And NaCl has atoms of Na (sodium) and Cl (chlorine), chemicaly bonded, in a fixed ratio (1:1).


There are only 118 known elements and you can find them in any modern periodic table. Therer are virtually infinitely many compounds since many different combinations of the elements can be attained.


Elements and compounds have in common that they are classified as pure substances.


7 0
4 years ago
A sample of carbon dioxide at RTP is 0.50 dm3. How many grams of carbon dioxide do we have?
prohojiy [21]

Answer:

0.924 g

Explanation:

The following data were obtained from the question:

Volume of CO2 at RTP = 0.50 dm³

Mass of CO2 =?

Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:

1 mole of gas = 24 dm³ at RTP

Thus,

1 mole of CO2 occupies 24 dm³ at RTP.

Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e

Xmol of CO2 = 0.5 /24

Xmol of CO2 = 0.021 mole

Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.

Finally, we shall determine the mass of CO2 as follow:

Mole of CO2 = 0.021 mole

Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol

Mass of CO2 =?

Mole = mass /Molar mass

0.021 = mass of CO2 /44

Cross multiply

Mass of CO2 = 0.021 × 44

Mass of CO2 = 0.924 g.

3 0
3 years ago
An aqueous HCL solution has a proton concentration equal to 6.00 mol/L. The HCL concentration in this solution is ————M.
Harman [31]

Answer:

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4 0
4 years ago
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solniwko [45]

The balanced equation of the reaction shows that the mole of atoms on both sides of the reaction are equal.

<h3>What are balanced chemical equations?</h3>

Balanced chemical equations are equations in wgich the moles of each species on both sides of the reaction are equal.

To balance chemical equations, numerical coefficients are placed in front of the species in the reaction.

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Therefore, the balanced equation of the reaction shows that the mole of atoms on both sides of the reaction are equal.

Learn more about balancing equations at: brainly.com/question/11904811

#SPJ1

7 0
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