Answer:
V₂ = 106.5 mL
Explanation:
Given data:
Initial volume =200 mL
Initial pressure = 2 atm
Initial temperature = 35 °C (35 +273 = 308 K)
Final temperature = 55°C (55+273 = 328 K)
Final volume = ?
Final pressure = 4 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2 atm ×200 mL × 328 K / 308 K ×4 atm
V₂ = 131200 atm .mL. K / 1232 K.atm
V₂ = 106.5 mL
Answer:
Final concentration = 0.019 M
Explanation:
Initial Concentration [A]o = 0.27M
Rate constant, k = 0.75 s^-1
Final concentration [A] = ?
Time, t = 1.5s
The relationship between the variables is given by the equation;
ln[A] = ln[A]o - kt
ln[A] = ln(0.27) - (0.75)(1.5)
ln[A] = - 1.309 - 1.125
ln[A] = - 2.434
[A] = 0.019 M
Answer:
They dissolve easily in the body’s fluids
At an optimum pH of 7.0, there are more molecules per minute in all amounts of substrate thus this pH is ideal for maximum growth. 5. Enzymes function most efficiently at the temperature of a typical cell, which is 37 degrees Celsius. Increases or decreases in temperature can significantly lower the reaction rate.
Answer:
Volume of the solutions
This is the most important factor for her to control.
