Answer:
The atoms are vibrating in place.
Explanation:
One of the properties of an ionic substance is the possession of a crystalline structure. As Gerry observed the salt under a microscope, he discovered that it has a crystalline structure. Crystalline salts are all ionic in nature, hence the salt observed by Gerry is an ionic salt.
Solids containing a definite crystalline structure always has their particles vibrating in place. This is immediately evident as Gerry looks at the salt through a microscope.
The compound HF is an acid. This is because it dissociates in water to give hydrogen ions (H⁺) as the only positively charged ions.
The others dissociate as follows: NH₃ reacts with water to form an alkaline solution NH₄OH.
LiF dissolves to form an ionic solution
KOH dissociates in water to form an alkaline solution.
Answer:
I think the answer is a generator
Answer:
Reducing molecules.
Explanation:
NAD (Nicotinamide adenine dinucleotide) is the important molecule used by the living organisms for the generation of ATP. NADH is used almost in every biochemical cycle like glycolysis, kreb cycle and elelctron transport chain.
The NADH molecule is used as the reducing molecule in the biosynthesis of the different reaction. The NADH molecule reduces its hydrogen ions and also carry electrons for the synthesis of molecules. The NADH molecule is also used in the shuttle system as well.
Thus, the answer is reducing molecules.
Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.
<h3>
What is the keto-enol means in tautomer?</h3>
They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.
- The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
- If the ketone have been handled with bromine, little response might be visible because the enol content material might be too low.
- If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
- This might finally provide a bromoform product. Under acidic conditions, the enol might desire formation of the greater substituted enol constant with alkene stability.
