a electron behavior is a subatomic particle whose electric i charge and the other one is a molecule and chemical bond that shares electrons
The number of oxygen atoms is in 5.00 g of sample of sodium dichromate, Na₂Cr₂O₇ is 1.125 x 10²³ atoms.
<h3>What is sodium dichromate?</h3>
Sodium dichromate is an inorganic compound. It is sued in tanning and mental illness.
The molar mass of sodium = 23 gm
The molar mass of Cr = 51.99 gm
The molar mass of oxygen = 16 gm
Molar mass of Na₂Cr₂O₇ = 2(23) + 2(51.99) + 7(16) = 261.98 gm
Number of moles in 7 gm = mass / molar mass = 7 / 261.98 = 0.0267 moles
1 mole of Na₂Cr₂O₇ contains 7 moles of oxygen, therefore:
The number of moles of oxygen in 0.0267 moles = 0.0267 x 7 = 0.1869 moles
Thus, the number of atoms = 0.1869 x 6.02 x 10^23 = 1.125 x 10²³ atoms.
To learn more about sodium dichromate, refer to the link:
brainly.com/question/1444529
#SPJ4
Answer: The smallest unit of matter.
Explanation:
Answer:
A condensate is a liquid formed by condensation.
Explanation:
Answer:
1) D; 2) B
Explanation:
1) <em>Conservation of atoms
</em>
D is correct.
It has four atoms of H and two of O on each side of the reaction arrow.
A. <em>Wrong</em>. It has the same number of H and O on each side, but it has the <em>wrong product</em>. The reaction forms O₂ molecules, not O atoms.
B. <em>Wrong</em>. Atoms are balanced, but the <em>products are incorrect</em>.
C. <em>Wrong</em>. Atoms are balanced, but the <em>reactants are incorrect</em>.
===============
2) <em>Chemical equations
</em>
B is correct.
The atoms are balanced, and the equation shows the correct formulas of the molecules.
A. <em>Wrong</em>. Atoms are balanced, and the formulas are correct, but the equation is <em>not in its simplest form</em>. The coefficients are not in their lowest terms. We must divide every coefficient by six to get the correct equation: H₂ + Cl₂ ⟶ 2HCl.
C. <em>Wrong</em>. The <em>reactants are incorrect</em>, and the equation is <em>not in its lowest terms</em>.
D. <em>Wrong</em>. The <em>reactants are incorrect</em>.
