Answer:
Equilibrium concentration of
is 12.5 M
Explanation:
Given reaction: 
Here, ![K_{c}=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}][H_{2}O]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BC_%7B2%7DH_%7B5%7DOH%5D%7D%7B%5BC_%7B2%7DH_%7B4%7D%5D%5BH_%7B2%7DO%5D%7D)
where
represents equilibrium constant in terms of concentration and species inside third bracket represent equilibrium concentrations
Here,
,
and 
So, ![[H_{2}O]=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}]\times K_{c}}=\frac{1.69}{0.015\times 9.0}=12.5M](https://tex.z-dn.net/?f=%5BH_%7B2%7DO%5D%3D%5Cfrac%7B%5BC_%7B2%7DH_%7B5%7DOH%5D%7D%7B%5BC_%7B2%7DH_%7B4%7D%5D%5Ctimes%20K_%7Bc%7D%7D%3D%5Cfrac%7B1.69%7D%7B0.015%5Ctimes%209.0%7D%3D12.5M)
Hence equilibrium concentration of
is 12.5 M
The answer to this question would be: the anion uptake will be decreased
If proton pump function is decreased, that means the amount of proton that goes outside the cell will be decreased. It will cause the anion uptake decreased too because some anion needs to go inside cells by co transporting with the proton.
Answer:
See explanation
Explanation:
The mole refers to the amount of substance contained in 12 g of carbon-12. It was arbitrarily related to the number of elementary entities in 12 g of carbon -12 by Prof. Avogadro.
The number of moles of a substance is obtained as the mass of the substance divided by the mass of one mole of the substance (molar mass). Hence when the number of moles is known, the mass is now;
number of moles * molar mass
22.4L.
This is because the standard conversion factor for Liters is 22.4 and in the question it explicitly states liters of CO2.
Therefore, in order to convert Liters of CO2 to Moles of CO2, you'd need to use the conversion factor of 22.4.
Hope this helps!