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3 years ago

Most of earths carbon is in the atmosphere in the form of ___

Chemistry

1 answer:

ANEK [815]3 years ago

4 0

<span>Most of earths carbon is in the atmosphere in the form of a gas?</span>

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[HELP PLEASE] Describe the difference between the ways valence electrons are rearranged when forming ionic bonds and covalent bo

nydimaria [60]

Answer:

Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.

Explanation:

5 0

3 years ago

Drag and drop the labels provided into the boxes below to explain how the Earth-Sun-Moon system results in these seasons on Eart

GalinKa [24]

In order: tilted, rotates, revolving.

6 0

3 years ago

What reaction is zinc(s) + water(l) →

Marat540 [252]

Answer:

Zn+H2O ------ ZnO + H2 is the correct answer

8 0

3 years ago

Read 2 more answers

Plzzz help do your best to answer these questions

vovikov84 [41]

The empirical formula is the simplest formula of a chemical compound.

To find the empirical formula, we take the following steps;

Divide the percentage by mass of each element by its relative atomic mass.
Divide the quotient of each by the lowest value obtained instep 1 above
Write the result of step 2 above as the subscript following each atom.

1) O - 88.10/16, H - 11.190/1

O - 5.5, H - 11.19

O - 5.5/5.5, H - 11.19/5.5

O - 1, H - 2

Empirical formula = OH2

2) C - 41.368/12 H - 8.101/1, N - 32.162/14, O - 18.369/16

C - 3, H - 8, N - 2, O - 1

C - 3/1, H - 8/1 N - 2/1 O - 1/1

C - 3, H - 8, N - 2, O - 1

Empirical formula = C3H8N2O

To obtain the molecular formula where n = number of atoms of each element;

Molecular weight = 174.204 g/mol

[ 3(12) + 8(1) + 2(14) + 16]n = 174

n= 174/88

n = 2 (to the nearest whole number)

Hence, we have;

[C3H8N2O]2

The molecular formula is C6H16N4O2

3) C - 19.999/12, H - 6.713/1, N - 46.646/14, O - 26.641/16

C - 2, H - 7, N - 3, O - 2

C - 2/2, H - 7/2, N - 3/2, O - 2/2

C - 1, H - 4, N - 2, O - 1

Empirical formula - CH4N2O

brainly.com/question/1363167

5 0

3 years ago

If the caterpillar keeps moving at the same speed, how long will it take to travel 6cm?

Solnce55 [7]

It will take 15 s to travel 6 cm

<h3>Further explanation</h3>

Given

distance versus time graph

Required

time travel

Solution

Caterpillar motion is a straight motion with a constant speed, so that the graph between distance and time forms a diagonal line

If we look at the graph, we can determine the time taken when the distance reaches 6 cm (y axis) by drawing a line to the diagonal line and cutting the x-axis as time, and we get 15 s

Or we can also use the formula for motion at constant speed:

d = v x t

With v at point 2,5 of 2/5 m / s, so the time taken:

$\tt t=\dfrac{d}{v}=\dfrac{6}{2/5}=15~s$

4 0

3 years ago