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Anika [276]
3 years ago
8

Most of earths carbon is in the atmosphere in the form of ___

Chemistry
1 answer:
ANEK [815]3 years ago
4 0
<span>Most of earths carbon is in the atmosphere in the form of  a gas?</span>
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A nucleus with four protons has a total positive charge of _____
vlada-n [284]
this would have a charge of 4 plus
8 0
3 years ago
Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g), Kgoal=? by making use of the followi
marta [7]

Answer : The value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

Explanation :

The following equilibrium reactions are :

(1) 2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2 K_1=5.40\times 10^{-16}

(2) 2H_2(g)+O_2(g)\rightleftharpoons 2H_2O(l) K_2=1.06\times 10^{10}

(3) CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g) K_3=2.68\times 10^{-9}

The final equilibrium reaction is :

CO_2(g)\rightleftharpoons C(s)+O_2(g) K_{goal}=?

Now we have to calculate the value of K_{goal} for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

K_{goal}=\sqrt{K_1\times K_2\times K_3}

Now put all the given values in this expression, we get :

K_{goal}=\sqrt{(5.40\times 10^{-16})\times (1.06\times 10^{10})\times (2.68\times 10^{-9})}

K_{goal}=1.238\times 10^{-7}

Therefore, the value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

3 0
3 years ago
B) Name three substances which can undergo sublimation and deposition respectively​
SpyIntel [72]

solid carbon dioxide, iodine, arsenic, and naphthalene

Explanation:

Examples of substances that undergo sublimation

Examples of solids that sublime are dry ice (solid carbon dioxide), iodine, arsenic, and naphthalene (the stuff mothballs are made of).

3 0
3 years ago
Percent concentration is one of the most common and basic concentration measurement used by general public. true or false?
Aleksandr [31]

Answer:

  • <u>TRUE:</u> <em>Percent concentration is one of the most common and basic concentration measurement used by general public</em>

Explanation:

In chemistry there are many <em>concentration measurements</em> used to describe the mixtures. Some of them are, percent, molarity, molality, and molar fraction, among others.

Percent concentration is a popular one because it is commonly understood and used by the non specialist people, i.e. general public.

The percent concentration of a component is defined as: (amount of component in the mixture / amount of mixture) × 100.

The amounts may be measured in mass units (e.g grams) or volume units (e.g. mililiters).

For solutions, mass percent concentration is:

  • % = (mass of solute / mass of solution) × 100.

And voluem percen contration is:

  • % = (volume of solute / volume of solution) × 100

Since percentage is used in many profesional and personal activities, most persons use it.

For example, rubbing alcohol, that everyone buys in pharmacies, is 70%; vinager, used in the food, is acetic acid at 5% - 8%.

5 0
3 years ago
What mass of H2 is needed to react with 8.5 g of O2 according to the following equation G plus O2 (G)plus H2 ( G)?
Rzqust [24]
The correct answer is number 1
5 0
3 years ago
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