Answer:
hello your question is incomplete below is the missing part
Ex = 0
Ey = 
Explanation:
Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π
Ex = 0
Ey = 
<h2>
Answer: Marie Curie's notebooks</h2>
Explanation:
Marie Curie's notebooks, as well as all of her belongings, including her clothes, were contaminated with ionizing radiation. In fact, also those of her husband, because <u>this couple of scientists discovered the radioactivity of several elements</u>, helping the advance of science, but did not know about the consequences of dealing with these materials without adequate protection.
It should be noted that Curie's notes are stored in the basements of the National Library of France, stored in thick lead boxes and those who wish to access these documents must follow the appropriate protocol to treat radioactive material, wear appropriate clothing and sign a responsibility agreement before allowing them to review the documents.
Answer:
The magnitude of F when t=4 s=146.64 N
Explanation:
We are given that
Mass of crate,m=6.00 kg
Height of crate above its initial position is given by

We have to find the magnitude of F when t=4.00 s
Differentiate w.r.t t
![\frac{dy}{dt]=2.8+3(0.61)t^2](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%5D%3D2.8%2B3%280.61%29t%5E2)



Now, magnitude of force

Hence, the magnitude of F when t=4 s=146.64 N
<span>Matching the boundary with its characteristics
1. Convergent - C. Compression
2. Divergent - B. Along ocean ridges
3. Transform - A. Along strike-slip faults
The compression that occur in the convergent boundary causes the reverse fault in the earth crust.
So in the divergent boundary two crust plates move apart causing a normal fault along the ocean ridges.
The faults in the transform boundary happens at the place where plates slide laterally.</span>
Answer:
The recoil velocity of the projectile is 0.0025m/s
Explanation:
Given:
Mass of the projectile =0.005kg
Mass of the launcher = 1500kg
Velocity = 750 m/s.
To Find:
The recoil velocity of the projectile = ?
Solution:
The recoil velocity is the obtained by dividing the "recoil momentum" by the "mass of the recoil body". The recoil momentum is equal to the momentum of the other body.
The momentum of the other body is equal to it mass times its velocity.
Lets find the recoil momentum,
Recoil momentum = mass of the projectile X velocity
Recoil momentum =
Recoil momentum = 3.75
Now Recoil Velocity,
Recoil Velocity = 
Recoil Velocity = 
Recoil Velocity = 0.0025m/s