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Bezzdna [24]
3 years ago
12

Jason fought in the war in Iraq and witnessed some horrific sights. When he got home from the war, Jason didn't seem to remember

these shocking events anymore. What happened?
Jason probably has repressed the memories.
Jason's experiences were stored in his false memory.
Jason has amnesia.
Physics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

Jason has amnesia.

Explanation:

Amnesia is a kind of memory loss. Some people cannot learn new things and this is known as anterograde amnesia. Some people forget events from their past and this is called as retrograde amnesia. Jason has retrograde amnesia because he has forgotten his past events. The causes for this disease are given below:

i) Brain injuries  

ii) Certain drugs and alcohol  

iii) Traumatic events  

zimovet [89]3 years ago
7 0

Answer:

Jason has repressed the memories

Explanation:

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The greatest wind speed recorded on Earth’s surface is 231 miles per hour. What is the speed in kilometers per hour?
Contact [7]
It would be  371.758hole this helps

4 0
3 years ago
An electron moves in a circular path perpendicular to a constant magnetic field with a magnitude of 2.50 mT. The angular momentu
liberstina [14]

Answer:

Explanation:

The angular momentum of electron mvR = 6 x 10⁻²⁵  Js

Magnetic field B = 2.5 x 10⁻³ T

radius of circular path R = mv / Bq

where m is mass , v is velocity and q is charge on electron

R² = mvR / Bq

R² = 6 x 10⁻²⁵ / 2.5 x 10⁻³ x 1.6 x 10⁻¹⁹

= 1.5 x 10⁻³

R = 3.87 x 10⁻² m

mvR = 6 x 10⁻²⁵

v = 6 x 10⁻²⁵  / mR

= 6 x 10⁻²⁵  / 9.1 x 10⁻³¹ x 3.87 x 10⁻²

= .17 x 10⁸

= 17 x 10⁶ m/s

6 0
3 years ago
Educación física como se puede mejorar la técnica deportiva
motikmotik

Answer:

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Realice un seguimiento y mida su rendimiento durante el entrenamiento. ...

Haga de la hidratación adecuada una prioridad. ...

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Explanation:

8 0
2 years ago
Consider a string with a length of (47.5 A) cm tied at both end (like on a stringed instrument). If the frequency of the first h
zubka84 [21]

To solve this problem it is necessary to apply the concepts related to wavelength as a function of frequency and speed, as well as to determine the wavelength as a function of length.

From the harmonic vibration generated we know that the total length of the string will be equivalent to a half of the wavelength, that is

L = \frac{\lambda}{2} \rightarrow \lambda = 2L

Where,

\lambda = Wavelength

Therefore the wavelength for us would be,

\lambda = 2*47.5cm = 95cm = 0.95m

From the relationship of speed, frequency and wavelength we know that

\lambda = \frac{v}{f} \rightarrow v = \lambda f

v = (0.95m)(245Hz)

v = 232.75 m/s

Therefore the speed of the wave is 232.75m/s

4 0
3 years ago
Water is circulating through a closed system of pipes in a two floor apartment. On the first floor, the water has a gauge pressu
anastassius [24]

Answer:

The value of gauge pressure at outlet = -38557.224 pascal

Explanation:

Apply Bernoulli' s Equation

\frac{P_{1}}{9810} + \frac{V_{1} ^{2}}{19.62} + h_{1} = \frac{P_{2}}{9810} + \frac{V_{2} ^{2}}{19.62} + h_{2} --------------(1)

Where

P_{1} =  Gauge pressure at inlet = 3.70105 pascal

V_{1} = velocity at inlet =  2.4 \frac{m}{sec}

P_{2} = Gauge pressure at outlet = we have to calculate

V_{2} = velocity at outlet = 3.5 \frac{m}{sec}

h_{2} - h_{1} = 3.6 m

Put all the values in equation (1) we get,

⇒ \frac{3.70105}{9810} + \frac{2.4 ^{2}}{19.62} = \frac{P_{2}}{9810} + \frac{3.5 ^{2}}{19.62} + 3.6

⇒ 0.294 = \frac{P_{2}}{9810} + 0.6244 + 3.6

⇒ \frac{P_{2}}{9810} = 0.294 - 0.6244 - 3.6

⇒ \frac{P_{2}}{9810} = - 3.9304

⇒ P_{2} = - 38557.224 pascal

This is the value of gauge pressure at outlet.

3 0
3 years ago
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