1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrews [41]
3 years ago
6

A 7.00 kg mass is being pulled by a 53.8 n force what is the acceleration

Physics
1 answer:
mixas84 [53]3 years ago
7 0

Answer:

a = 7.69m/s^2

Explanation:

Force = mass x acceleration

Given Force F = 53.8N

Mass M = 7.00kg

Using the above formula

53.8 = 7.00 x a

Divide both sides by 7.0

53.8/7.00 = 7.00 x a /7.00

7.69 = a

a = 7.69m/s^2

You might be interested in
Two gliders are on a frictionless, level air track. Both gliders are free to move. Initially, glider A moves to the right and gl
Yuliya22 [10]

Answer:

The change in momentum of both objects is the same but in opposite direction.

Explanation:

Hi there!

The momentum of the system is calculated as the sum of the momentums of each glider. The momentum of the system is conserved if no external force is acting on the objects (as in this case). That means that the initial momentum of the system is equal to the final momentum of the system.

The momentum of each glider is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass of the glider.

v = velocity.

The momentum of the system for glider A and B can be calculated as follows:

initial momentum = mA · vA + mB · vB

Where:

mA and vA = mass and velocity of glider A

mB and vB = mass and velocity of glider B

Initially, glider B is at rest so that vB = 0. Then, the initial momentum of the system is:

initial momentum = mA · vA

The final momentum of the system is calculated as follows:

final momentum = mA · vA´ + mB · vB´

Where vA´ and vB´ are the final velocities of glider A and B respectively.

We know that mB = 4mA and that vA´ is negative. The the final momentum will be:

final momentum = -mA · vA´ + 4mA · vB´

Since initial momentum = final momentum:

mA · vA = -mA · vA´ + 4mA · vB´

mA · vA + mA · vA´ = 4mA · vB´

<u>vA + vA´ = 4 vB´</u>

<u />

The change in momentum of glider A (ΔpA) is calculated as follows:

ΔpA = final momentum - initial momentum

ΔpA =  -mA · vA´ - mA · vA = -mA (vA + vA´) = -4mA · vB´

The change in momentum of glider B (ΔpB) is calculated as follows:

ΔpB = final momentum - initial momentum

ΔpB = 4mA · vB´ - 0 = 4mA · vB´

Then, the change in momentum of both objects is the same but in opposite direction. That´s why the momentum is conserved.

4 0
2 years ago
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains
Vikki [24]
Hey i dont have an answer but i need the points for finals today. Thank you
6 0
3 years ago
Read 2 more answers
which best describes what happens with the sonar to sound pulses from a ship after they hit the ocean floor?
lakkis [162]

Answer:

With sonar, what happens to sound pulses from a ship after they hit the ocean floor? ... They bounce back to the ship.

Explanation:

3 0
3 years ago
The deck of a bridge is suspended 235 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
Aleks04 [339]

Answer:

(a) 1, average velocity = -65.6 m/s

   2, average velocity = -64.8 m/s

   3, average velocity = -64.16 m/s

(b) The instantaneous velocity is -96 m/s

Explanation:

(a)

Average velocity is given  by;

y(t_2,t_1) = \frac{y(t_2) - y(t_1)}{t_2-t_1}

(1)

y(2.1,2) = \frac{(235-16*2.1^2) - (235-16*2^2)}{2.1-2}\\\\ y(2.1,2) = -65.6 \ m/s

(2)

y(2.05,2) = \frac{(235-16*2.05^2) - (235-16*2^2)}{2.05-2}\\\\ y(2.05,2) = -64.8 \ m/s

(3)

y(2.01,2) = \frac{(235-16*2.01^2) - (235-16*2^2)}{2.01-2}\\\\ y(2.01,2) = -64.16 \ m/s

b. y = 235 - 16t²

The instantaneous velocity is given by;

v = dy /dt

dy / dt = -32t

when t = 3 s

v = -32(3)

v = -96 m/s

5 0
3 years ago
A simple pendulum 2 m long swings through a maximum angle of 30 ∘ with the vertical. part a calculate its period assuming a smal
victus00 [196]

Length of the pendulum (l) = 2 m

Acceleration due to gravity = g = 9.8 m/s^2

For small amplitude, the pendulum will undergo simple harmonic motion.

Hence, the time period of the pendulum for small amplitude = 2\pi \sqrt{\frac{l}{g} }

Now, plug the values of l and g

T = 2\pi \sqrt{\frac{2}{9.8} }

T = 2 × 3.14 × 0.451

T = 2.83 seconds

Hence, the time period of the pendulum for small amplitude = 2.83 s

3 0
2 years ago
Read 2 more answers
Other questions:
  • If a negatively charged particle moves into a magnetic field traveling in a straight line, how would you expect its motion to ch
    7·2 answers
  • A baseball is thrown vertically up to a height of 30 m on Earth. If the same ball is thrown up on the moon with the same initial
    6·1 answer
  • Please help me with this. Finding speed.
    15·2 answers
  • →15 points← Waiting for his new game to come in the mail, Billy races up the stairs in 3 seconds from the basement whenever he h
    15·1 answer
  • What is the mechanical adventure of a machine with an input force of 63 pounds and an output force of 275 pounds?
    8·1 answer
  • CAN SOMEONE HELP PLEASE
    8·1 answer
  • What is the gradual process through which humans change from birth to<br> adulthood?
    11·1 answer
  • What happens when two charged objects physically contact each other?
    11·1 answer
  • A period of one year on Earth is the time it takes Earth to
    11·1 answer
  • Problem 6. A negatively charged particle is placed in a uniform electric field directed
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!