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Travka [436]
3 years ago
13

Is that right? I feel like it is but im not too sure i need help fast pleasee

Mathematics
1 answer:
slamgirl [31]3 years ago
5 0

yes it should be the answer

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Find the value of x.
KatRina [158]

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A or B

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Two thirds of a number is no more than -10
Aliun [14]
Let x be the number in the problem. When it states that x is "no more than -10", it means than it is less than or equal to -10. So, we have

\frac{2}{3}x≤-10

In order to cancel out the \frac{2}{3} on the left and isolate x, we multiply both sides by \frac{3}{2} (since \frac{3}{2}·\frac{2}{3}=1). Thus, we have

x≤-10·\frac{3}{2}=-15

Therefore, x≤-15

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5 is 5% of what number?​
iragen [17]

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Triangle A E C is shown. Line segment B D is drawn near point C to form triangle B D C.
AVprozaik [17]

∠BDC and ∠AED are right angles, is  a piece of additional information is appropriate to prove △ CEA ~ △ CDB

Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.

<h3> What are Similar triangles?</h3>

Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.

Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)

Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.

Learn more about similar triangles here:
brainly.com/question/25882965

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3 0
1 year ago
Triangles L M N and L K N are connected at side L N. A line is drawn from point M to point K and intersects side L N at point P.
lesya692 [45]

The true statement is Line MK is the perpendicular bisector of LN and ML is ≅  MN.

<h3>What is perpendicular?</h3>

Perpendicular lines are lines that intersect at a right (90 degrees) angle.

Given:

Δ LMN and Δ LKN are connected at side LN.

As per the information,

Line MK is the perpendicular bisector of LN. and ML ≅  MN.

Learn  ore about this concept here:

brainly.com/question/25397944

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8 0
1 year ago
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