All categories

2 years ago

You start at (2, 7). You move up 3 units. Where do you end?

Mathematics

2 answers:

Kryger [21]2 years ago

7 0

Answer:

(2, 10)

Step-by-step explanation:

Since we are only focusing on vertical movement, we are looking at the y-value. We are moving up 3 units, so we just add 3 to 7 to get 10.

mestny [16]2 years ago

6 0

Answer:

2,10

Step-by-step explanation:

The X-axis goes horizontally, and the Y-axis goes vertically, and when doing these coordinate like things, the X-axis goes first, and the Y-axis goes second. So 2 is the X-axis, and 7 is the Y-axis. So if you have to move up 3 units, you have to add 3 to 7, because 7 is vertical and 2 is horizontal.

You might be interested in

You have 2000 grams of substance A which has decay constant 0.03, and you have 3000 grams of substance B, which has decay consta

joja [24]

Answer:

If you have a quantity X of a substance, with a decay constant r, then the equation that tells you the amount of substance that you have, at a time t, is:

C(t) = X*e^(-r*t)

Now, we know that:

We have 2000g of substance A, and it has a decay constant of 0.03 (i assume that is in 1/year because the question asks in years)

And we have 3000 grams of substance B, with a decay constant of 0.05.

Then the equations for both of them will be:

Ca = 2000g*e^(-0.03*t)

Cb = 3000g*e^(-0.05*t)

Where t is in years.

We want to find the value of t such that Ca = Cb.

So we need to solve:

2000g*e^(-0.03*t) = 3000g*e^(-0.05*t)

e^(-0.03*t) = (3/2)e^(-0.05*t)

e^(-0.03*t)/e^(-0.05*t) = 3/2

e^(t*(0.05 - 0.03)) = 3/2

e^(t*0.02) = 3/2

Now we can apply Ln(x) to both sides, and get:

Ln(e^(t*0.02)) = Ln(3/2)

t*0.02 = Ln(3/2)

t = Ln(3/2)/0.02 = 20.3

Then after 20.3 years, both substances will have the same mass.

6 0

2 years ago

Which relation describes a function?

Kisachek [45]

Answer:

{(-2, -3), (-3, -2), (2,3), (3, 2)}

Step-by-step explanation:

A function is a set of ordered pairs in which no two pairs have the same first number.

In other words, an x cannot be paired with two y's.

A function takes an x and pairs it with one and only one y.

{(0,0), (0, 2), (2.0), (2, 2)} is not a function because it pairs 0 with both 0 and 2.

{(2,-1), (2, 1), (3,-1), (3, 1)} is not a function because it pairs 2 with both -1 and 1.

{(2, 2), (2, 3), (3, 2), (3, 3)} is not a function because it pairs 2 with both 2 and 3.

8 0

3 years ago

Read 2 more answers

Solve for x. Write the reasons next to each step. (2x - 6) (x + 40)

solniwko [45]

Answer:

The answer for first one is,

$2(x - 3)$

sorry I don't know the answer for second one.

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=4a%20-%20%283a%20-%202b%29%20%2B%203a" id="TexFormula1" title="4a - (3a - 2b) + 3a" alt="4a -

MAVERICK [17]

4a - (3a - 2b) + 3a

4a - 3a + 2b + 3a

a + 2b + 3a

4a + 2b

2.(2a + b)

4 0

3 years ago

Help me thanks please thanks

Gnesinka [82]

83838383 centimeters

4 0

3 years ago

Read 2 more answers