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AleksAgata [21]
2 years ago
14

Which of the following statements are true about chemical substances and processes? Check all that apply.

Chemistry
1 answer:
kolbaska11 [484]2 years ago
8 0

Answer:

Chemical processes can be types of biological processes.

Chemical substances can be found in the bloodstream.

Chemical processes work to maintain homeostasis.

Explanation:

The listed three choices are true statements about chemical processes. Chemical processes brings about chemical change and they occur in biological organisms.

Some examples of chemical processes in organisms is metabolism of food.

Also, chemical processes can help regulate the internal environment of an organism. It is known that chemical reactions at certain times acts a thermoregulators in the body.

Examples of chemical substances in the body are glucose, amino acid, proteins etc.

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1. Determine the molarity given 0.6762 mol KOH and a volume of<br> 500.00 mL.
astra-53 [7]

Answer:

1.352 M

Explanation:

Molarity is equal to the moles of the substance divided by the volume in Liters. First convert mL to L. 500.00 mL is 0.50000 L. Divide 0.6762 by 0.5 and remember to keep a maximum of 4 significant figures. :)

8 0
3 years ago
What is the oxidation state of cr in CrPO4 and Cr3(PO4)2?
soldi70 [24.7K]

Answer:

Explanation:

Oxidation state of Cr in CrPO₄

As a general rule, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero.

The compound above is in its neutral state and we sum all the oxidation numbers and equate to zero:

The oxidation number of P is -2

                                           O is -2

Let the oxidation number of Cr be x:

                              x + (-2) + 4(-2) = 0

                              x -2-8 = 0

                               x -10 = 0

                                x = +10

For Cr in Cr₃(PO₄)₂

         Using the same rule:

        2(x) + 2[-2 + 4(-2)] = 0

           2x + 2(-2-8) = 0

            2x -20 = 0

                x = +10

6 0
3 years ago
Read 2 more answers
How is the Scientific Method used in science?
xeze [42]

Answer:

to collect measurable, empirical evidence in an experiment related to a hypothesis the results aiming to support or contradict a theory.

Explanation:

7 0
3 years ago
At the normal melting point of NaCl, 801 degrees C, its enthalpy of fusion is 28.8 kJ / mol. The density of the solid is 2.165 g
melisa1 [442]

<u>Answer:</u> The increase in pressure is 0.003 atm

<u>Explanation:</u>

To calculate the final pressure, we use the Clausius-Clayperon equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = initial pressure which is the pressure at normal boiling point = 1 atm

P_2 = final pressure = ?

\Delta H = Enthalpy change of the reaction = 28.8 kJ/mol = 28800 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 801^oC=[801+273]K=1074K

T_2 = final temperature = (801+1.00)^oC=802.00=[802+273]K=1075K

Putting values in above equation, we get:

\ln(\frac{P_2}{1})=\frac{28800J/mol}{8.314J/mol.K}[\frac{1}{1074}-\frac{1}{1075}]\\\\\ln P_2=3\times 10^{-3}atm\\\\P_2=e^{3\times 10^{-3}}=1.003atm

Change in pressure = P_2-P_1=1.003-1.00=0.003atm

Hence, the increase in pressure is 0.003 atm

6 0
3 years ago
Iodine-131 is administered orally in the form of NaI(aq) as a treatment for thyroid cancer. The half-life of iodine-131 is 8.04
evablogger [386]

Answer:

16.6 mg

Explanation:

Step 1: Calculate the rate constant (k) for Iodine-131 decay

We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.

k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹

Step 2: Calculate the mass of iodine after 8.52 days

Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.

ln I = ln I₀ - k × t

ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day

I = 16.6 mg

8 0
3 years ago
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