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Lana71 [14]
3 years ago
10

Formula for Ni2+ and NO3

Chemistry
1 answer:
lyudmila [28]3 years ago
6 0

The formula of a compound is Ni(NO_3)_2

Given:

The ions Ni^{2+} and NO_3^-

To find:

The formula for ions Ni^{2+} and NO_3^-

Solution:

The ion with a positive charge (cation) = nickel ion = Ni^{2+}

The ion with a negative charge (anion) = nitrate ion = NO_3^-

Valency on nickel ion = 2

Valency on nitrate ion = 1

Using the criss-cross method as shown in image

The formula of a compound : Ni(NO_3)_2

The name of a compound is nickel(II) nitrate

Ni^{2+}+2NO_3^-\rightarrow Ni(NO_3)_2

The formula of a compound is Ni(NO_3)_2

Learn more about ions here:

brainly.com/question/24389121?referrer=searchResults

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lbvjy [14]

Answer:

is a way of presenting information about the chemical proportions of atoms

Explanation:

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3 years ago
Which statement about climate is true?
Y_Kistochka [10]
I believe the answer is B!
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An independent variable is
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C

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a variable does that dose not depend on that of another

6 0
3 years ago
What mass of chromium would be produced from the reaction of 57.0 g of potassium with 199 g of chromium(II) bromide according to
fredd [130]

Answer:

Mass of Chromium produced = 37.91 grams

Explanation:

2K + CrBr₂  →  2KBr + Cr

2mole     1 mole                1 mole

mass of Potassium = 57.0 grams

molar mass of Potassium = 39.1 g/mol

no of moles of Potassium = 57.0 / 39.1 = 1.458 moles

mass of CrBr₂= 199 grams

molar mass of CrBr₂ = 211.8 gram/mole

no of moles of CrBr₂ = 199 / 211.8 = 0.939 mole

From chemical equation

1 mole of CrBr₂ = 2 moles of K

∴ 0.939 moles of CrBr₂ = ?

   ⇒ 0.939 x 2/1 = 1.878 moles of K

1.878 moles of K is needed, but there is 1.458 moles of K. So, Potassium is completed first during the reaction . Hence, Potassium is limiting reagent. and CrBr₂ is excess reagent .

From chemical equation

2 moles of K = 1 mole of Cr

∴ 1.458 moles of K = ?

   ⇒ 1.458 x 1/ 2 = 0.729 moles of Cr

no of moles of Cr formed = 0.729 moles

molar mass of Cr = 52.0 g/mol

mass of one mole of Cr = 52.0 grams

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mass of Chromium produced = 37.91 grams

6 0
3 years ago
Question 5
Stolb23 [73]

Answer:

There are 17.64% students received B+ grades.

Explanation:

It is given that,

Total number of students in chemistry class is 17

We need to find the percentage received by B+.

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Required percentage = P=\dfrac{3}{17}\times 100=17.64\%

So, there are 17.64% students received B+ grades.

8 0
3 years ago
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