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3 years ago

Formula for Ni2+ and NO3

Chemistry

1 answer:

lyudmila [28]3 years ago

6 0

The formula of a compound is $Ni(NO_3)_2$

Given:

The ions $Ni^{2+}$ and $NO_3^-$

To find:

The formula for ions $Ni^{2+}$ and $NO_3^-$

Solution:

The ion with a positive charge (cation) = nickel ion = $Ni^{2+}$

The ion with a negative charge (anion) = nitrate ion = $NO_3^-$

Valency on nickel ion = 2

Valency on nitrate ion = 1

Using the criss-cross method as shown in image

The formula of a compound : $Ni(NO_3)_2$

The name of a compound is nickel(II) nitrate

$Ni^{2+}+2NO_3^-\rightarrow Ni(NO_3)_2$

The formula of a compound is $Ni(NO_3)_2$

Learn more about ions here:

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frosja888 [35]

The chemical formula CH2O can be classified as Empirical formula and possibly a molecular formula. The empirical formula of a compound is the simplest formula that indicates the simplest ratio of atoms in the compound, while the molecular formula is the representation of the actual whole number ratio between the elements of the compound.

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3 years ago

If a black ball is denser than a white ball of the same size, what does the black ball have??

yKpoI14uk [10]

Answer: The black ball will have more mass than the white ball.

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Mathematically,

$Density=\frac{Mass}{Volume}$

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Sodium hydride reacts with excess water to produce aqueous sodium hydroxide and hydrogen gas:NaH (s) H2O (l) → NaOH (aq) H2 (g)A

Anuta_ua [19.1K]

NaH(s)+ H2O (l)=>NaOH(aq)+H2(g)

You want to calculate the mass of NaH, I assume. Otherwise, the question isn't clear. It simply says calculate the mass(??)

So, calculate the moles of H2 gas that satisfy the conditions of 982 ml at 28ºC and 765 torr. But you must subtract the vapor pressure of water at 28º to get the actual pressure of the H2 gas. So, the actual conditions are 982 ml (0.982 L) and 301 K and 765-28 = 737 torr.

PV = nRT

n = PV/RT = (737 torr)(0.982 L)/(62.4 L-torr/Kmol)(301 K)

n = 0.0385 moles H2

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Brainliest Please :)

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3 years ago

Read 2 more answers

Calculate the volume in mL of a 0.708 M KOH solution containing 0.098 mol of solute

Olenka [21]

Molarity = mol/liter

0.708M = 0.098mol/L
Rearrange to find L:
0.098mol/0.708M = .138L

For every liter there is 1000 mL:
.138L • 1000mL =138mL KOH

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4 years ago