In order to find the answer, use an ICE chart:
Ca(IO3)2...Ca2+......IO3-
<span>some.......0..........0 </span>
<span>less.......+x......+2x </span>
<span>less........x.........2x
</span>
<span>Ca(IO₃)₂ ⇄ Ca⁺² + 2 IO⁻³
</span>
K sp = [Ca⁺²][IO₃⁻]²
K sp = (x) (2 x)² = 4 x³
7.1 x 10⁻⁷ = 4 x³
<span>x = molar solubility = 5.6 x 10</span>⁻³ M
The answer is 5.6 x 10 ^ 3 M. (molar solubility)
Answer is: <span>b.20.0 L </span><span>liters of ammonia are needed to react completely.
</span>V(NO) = 30 L.
n(NO) = V(NO) ÷ Vm.
n(NO) = 30 L ÷ 22,4 L/mol.
n(NO) = 1,34 mol.
From chemical reaction: n(NO) : n(NH₃) = 6 : 4 (3 : 2).
n(NH₃) = 4 · 1,34 mol ÷ 6.
n(NH₃) = 0,892 mol.
V(NH₃) = 0,892 mol · 22,4 L/mol.
V(NH₃) = 20 L.
Answer:
In 7.80 g of styrene, we have 3.60×10²³ atoms of H
Explanation:
Empirical formula of styrene is CH
Molecular formula of styrene is C₈H₈
So, 1 mol of styrene has 8 moles of C and 8 moles of H and 1 mol weighs 104.14 grams. Let's make a rule of three:
104.14 g (1 mol of C₈H₈) have 8 moles of H
Then 7.80 g would have ( 7.80 .8) / 104.14 = 0.599 moles
As we know, 1 mol of anything has NA particles (Avogadro's Number, 6.02×10²³), so 0.599 moles will have (mol . NA) particles
0.599 mol . 6.02×10²³ atoms / 1 mol = 3.60×10²³ atoms
Answer: Payback time = 0.0075
Explanation: Since payback time is calculated as:
payback time = 
First determine the installation cost:
100 mm thick insulation covers 8.3 m². Then 300 mm covers 24.9 m².
To cover 8.3m² costs £20. Then, the cost to cover 24.9 m² is:
cost = 
cost = £60
The cost of putting the insulation is £120, so the total cost is:
total cost = £60 + £120
total cost = £180
Savings per year per 100 mm thick is £80. For 300 mm, the value of annual savings is:
savings = 
savings = 240
payback time =
payback time = 
payback time = 0.75
The heat of combustion for methanol is 727 kj/mol
<em><u>calculation</u></em>
calculate the moles of methanol (CH3OH)
moles = mass/molar mass
molar mass of methanol = 12 +( 1 x3) +16 + 1= 32 g /mol
moles is therefore= 64.0 g / 32 g/mol = 2 moles
Heat of combustion is therefore = 1454 Kj / 2 moles = 727 Kj/mol
