2BF₃ + 3Li₂SO₃ ----> B₂(SO₃)₃ + <u>6LiF
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Answer:
c. precipitation
Explanation:
Let's consider the following balanced net ionic equation.
Cl⁻(aq) + AgNO₃(ag) ⇒ AgCl(s) + NO₃⁻ (ag)
What kind of reaction is this?
a. acid-base. No, because the reactants are not acids and bases.
b. redox. No, because all the species have the same oxidation numbers in the reactants and the products
c. precipitation. Yes, because an insoluble compound (AgCl) is produced, which then precipitates.
Answer: 1560632 joules
Explanation:
The change in thermal energy (Q) required to heat ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Given that:
Q = ?
Mass of frozen water (ice) = 1kg
C = 4184 J/(kg K)
Φ = (Final temperature - Initial temperature)
= 100°C - 0°C = 100°C
Convert 100°C to Kelvin
(100°C + 273) = 373K
Then, Q = MCΦ
Q = 1kg x 4184 J/(kg K) x 373K
Q = 1560632 joules
Thus, the change in thermal energy is 1560632 joules
Answer:
Covalent Bonds
Explanation:
INTERmolecular forces are those that exist between molecules, so you can think of it liek international things taking place between countries. As you are aware, dipoles exist across an entire molecule, so for 2 dipoles to interact, there needs to be 2 molecules. Van der Waals forces also take place between molecules when there is an uneven distribution of electrons across a molecule, causing a temporary weak dipole. Hydrogen bonding is similar to dipole-dipole forces, but only happen when there is a hydrogen interacting with an atom on another molecule that has a lone pair of electrons.
Covalent bonds, however, are INTRAmolecular, meaning they are present within a molecule. Covalent bonds are the bonds that exist when two atoms, within the same molecule, share electrons so both can have a stable electron configuration.
Hope I helped! xx
The full question is shown in the image attached
Answer:
See explanation
Explanation:
In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.
When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;
1. 2-methyl propane
2. 2,4-dimethyl heptane
3. 2,2,3,3-tetramethyl butane
4. 5-ethyl-2,4-dimethyl octane
