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kaheart [24]
2 years ago
9

Which gasses each make up less than 1 percent of earths atmosphere

Chemistry
2 answers:
BARSIC [14]2 years ago
7 0

Answer:

Argon and Carbon dioxide

Explanation:

Although both nitrogen and oxygen are essential to human life on the planet, they have little effect on weather and other atmospheric processes. The variable components, which make up far less than 1 percent of the atmosphere, have a much greater influence on both short-term weather and long-term climate. For example, variations in water vapor in the atmosphere are familiar to us as relative humidity. Water vapor, CO2, CH4, N2O, and SO2 all have an important property: They absorb heat emitted by Earth and thus warm the atmosphere, creating what we call the "greenhouse effect."

In addition to gases, the atmosphere also contains particulate matter such as dust, volcanic ash, rain, and snow. These are, of course, highly variable and are generally less persistent than gas concentrations, but they can sometimes remain in the atmosphere for relatively long periods of time.

Brut [27]2 years ago
5 0

Answer:

argon, water vapor, carbon dioxide.

Explanation:

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Convert 5.00 moles of carbon to grams. Be sure to report your answer with the correct significant figures.
sergij07 [2.7K]

1 moles Carbon to grams = 12.0107 grams

2 moles Carbon to grams = 24.0214 grams

3 moles Carbon to grams = 36.0321 grams

4 moles Carbon to grams = 48.0428 grams

5 moles Carbon to grams = 60.0535 grams

6 moles Carbon to grams = 72.0642 grams

7 moles Carbon to grams = 84.0749 grams

8 moles Carbon to grams = 96.0856 grams

9 moles Carbon to grams = 108.0963 grams

10 moles Carbon to grams = 120.107 grams

8 0
2 years ago
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Zolol [24]

Your answer would be False

3 0
2 years ago
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A ball thrown across a football field is an example of a(n)
Cloud [144]

I don't know what you mean by the question, but in science it is Newton's second law.

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7 0
2 years ago
Nitrogen has an average atomic mass of 14.00674. it has two isotopes, n-14 and n-15, with atomic masses of 14.0031 amu and 15.00
masya89 [10]
In this case, we are going to assume that there are 100 atoms to make things easier. 

Let R% be the abundance of n-15. With this in mind, we calculate the abundance of n-14 to be 100%-R%

14.0031*(100-R)% + 15.001 * R%= 14.00674 
In this case, we can delete or ignore the % sign since we do not want to carry it around, however, we need to keep in mind that the final answer is in %

14.0031*(100-R) + 15.001 * R= 14.00674 
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Then, the abundance of n-15 is 0.3648%

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tia_tia [17]

Answer:

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Explanation:

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