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3 years ago

Which gasses each make up less than 1 percent of earths atmosphere

Chemistry

2 answers:

BARSIC [14]3 years ago

7 0

Answer:

Argon and Carbon dioxide

Explanation:

Although both nitrogen and oxygen are essential to human life on the planet, they have little effect on weather and other atmospheric processes. The variable components, which make up far less than 1 percent of the atmosphere, have a much greater influence on both short-term weather and long-term climate. For example, variations in water vapor in the atmosphere are familiar to us as relative humidity. Water vapor, CO2, CH4, N2O, and SO2 all have an important property: They absorb heat emitted by Earth and thus warm the atmosphere, creating what we call the "greenhouse effect."

In addition to gases, the atmosphere also contains particulate matter such as dust, volcanic ash, rain, and snow. These are, of course, highly variable and are generally less persistent than gas concentrations, but they can sometimes remain in the atmosphere for relatively long periods of time.

Brut [27]3 years ago

5 0

Answer:

argon, water vapor, carbon dioxide.

Explanation:

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How many moles of mgs2o3 are in 193 g of the compound?

Mashutka [201]

Answer:

1.414 Moles

Solution:

Data Given:

Mass of MgS₂O₃ = 193 g

M.Mass of MgS₂O₃ = 136.43 g.mol⁻¹

Moles = ?

Formula Used:

Moles = Mass ÷ M.Mass

Putting values,

Moles = 193 g ÷ 136.43 g.mol⁻¹

Moles = 1.414 mol

8 0

3 years ago

Entropy change in an internally reversible isothermal process is _______ to the temperature of the system.

alukav5142 [94]

Answer:

Internally reversible is the answer.

Explanation:

3 0

3 years ago

Cuantos moles de CO2 se requieren para reaccionar con 2 moles de Ba (OH)2

EastWind [94]

Answer:

hola soy jess, tu respuesta esta aqui

¿cuantos moles de CO2 se requiere para reaccionar 2 moles de Ba(OH)2

2 mol Ba(OH)₂ × \frac{1molCO_{2} }{1molBa (OH)_{2}}

1molBa(OH)

1molCO

= 2 moles CO₂

Explanation:

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3 0

3 years ago

A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

$-w=\frac{dm}{dt}$

w is the mass flow

m is the mass of salt

$-v*C=\frac{dm}{dt}$

v is the volume flow

C is the concentration

$C=\frac{m}{V+(6-3)*L/min*t}$

$-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}$

$-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}$

$-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}$

$-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)$

$-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)$

$m=90kg*[2000L/(2000L+3*L/min*t)]$

a) Initially: t=0

$m=90kg*[2000L/(2000L+3*L/min*0)]=90kg$

b) t=210 min (3.5 hr)

$m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg$

c) If time trends to infinity the division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0

3 years ago

Calculate AH for the reaction:<br> 2N2 (g) + 6H20 (g) → 302 (g) + 4NH3(g)

Ratling [72]

Answer:

Explanation:

4NH₃ (g) + 3O₂ (g) ⇒ 2N₂ (g) + 6H₂ O(1)

Δ $H_r={\sum}{ \Delta }H_f(\text{product})-{\sum}{ \Delta }H_f(\text{reactant})$

ΔH r =(2ΔH f(N 2 )+6ΔH f (H 2 O(l)))−(4ΔH f (NH 3 (g))+3ΔH f (O 2 (g)))

ΔH rex =[2×0+6×(−286)]−[4×(−46)+3×0]=−1716+186

ΔH rex =−1532kJ/mol

Thermodynamics is a branch of physical chemistry that studies heat and its effects and interactions. Governed by the four main laws, thermodynamics plays a huge role in physics and chemistry, and is also responsible for the law of conservation of energy, a fundamental rule in science.

7 0

1 year ago