We could tell a force is acting on an object if the object is being pushed, pulled, or moved in any way
1) 14g
2) 24 fl oz
3)10 cups
4)12 and 1/2 cups
Answer:
<h2>5N</h2>
Explanation:
To get the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle, we will have to resolve the force perpendicular to the wrench. Torque is the turning effect of a body or force about a point. It is similar to moments.
Torque = Force * radius
Note that the force must be perpendicular to the wrench. On resolving the force perpendicularly to the wrench, we will have to resolve the force to the vertical.
Fy = Fsinθ
Fy = 10sin30°
Fy = 10 * 0.5
Fy = 5N
<em>Torque = Fy * r</em>
<em>Given Fy = 5N and r = 20cm = 0.2m</em>
<em>Torque = 5 * 0.2</em>
<em>Torque = 1Nm</em>
<em />
<em>Hence the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle is 5N</em>
Answer:
The amplitude of the oscillating electric field is 1316.96 N/C
Explanation:
Given;
frequency of the wave, f = 2.4 Hz
intensity of the wave, I = 2300 W/m²
Amplitude of oscillating magnetic field is given by;
where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
I is intensity of wave
c is speed of light = 3 x 10⁸ m/s
The amplitude of the oscillating electric field is given by;
E₀ = cB₀
E₀ = 3 x 10⁸ x 4.3899 x 10⁻⁶
E₀ = 1316.96 N/C
Therefore, the amplitude of the oscillating electric field is 1316.96 N/C
