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3 years ago

Which of the following statements are true? Check all that apply.

Physics

1 answer:

lidiya [134]3 years ago

8 0

We have 6 levels and we will verify which of them is true.

A ) Electric charge is conserved

According to the conservation of charge, an electric charge can neither be created nor be destroyed.

Therefore this statement is TRUE.

B ) A positive charge and negative charge attract each other

According to the properties of charges, the opposite charges attract each other and similar charges repel each other

Therefore this statement is TRUE

C) Two positive charges attract each other.

Using the previous law, we can observe that this statement is false, because equal charges repel each other.

Therefore this statement is FALSE.

D ) Two negative charges repel each other.

Using the same principle as the two previous statements, two equal charges repel each other.

Therefore this statement is TRUE

E) Electric charge is quantized.

According to the quantization of charge, charges can take values only in integral multiples of a fundamental unit of charge.

Therefore this statement is TRUE.

F) A neutral object contains no charge.

A neutral object contains equal amount of negative and positive charge. Thus, in totality a neutral object contains no charge.

Therefore this statement is TRUE.

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A 0.5 m diameter wagon wheel consists of a thin rim having a mass of 7 kg and six spokes, each with a mass of 1.2 kg. 1.2 kg 7 k

Arte-miy333 [17]

Explanation:

It is given that,

Mass of the rim of wheel, m₁ = 7 kg

Mass of one spoke, m₂ = 1.2 kg

Diameter of the wagon, d = 0.5 m

Radius of the wagon, r = 0.25 m

Let I is the the moment of inertia of the wagon wheel for rotation about its axis.

We know that the moment of inertia of the ring is given by :

$I_1=m_1r^2$

$I_1=7\times (0.25)^2=0.437\ kgm^2$

The moment of inertia of the rod about one end is given by :

$I_2=\dfrac{m_2l^2}{3}$

l = r

$I_2=\dfrac{m_2r^2}{3}$

$I_2=\dfrac{1.2\times (0.25)^2}{3}=0.025\ kgm^2$

For 6 spokes, $I_2=0.025\times 6=0.15\ kgm^2$

So, the net moment of inertia of the wagon is :

$I=I_1+I_2$

$I=0.437+0.15=0.587\ kgm^2$

So, the moment of inertia of the wagon wheel for rotation about its axis is $0.587\ kgm^2$ . Hence, this is the required solution.

4 0

3 years ago

Initial velocity 10 m/s accelerates at 5 m/s for 2 seconds whats the final velocity

stiks02 [169]

Answer:

The final velocity is 20 m/s.

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, and t the time, the final speed can be calculated as follows:

$v_f=v_o+at$

The provided data is: vo=10 m/s, $a=5\ m/s^2$ , t=2 s. The final velocity is:

$v_f=10~m/s+5\ m/s^2\cdot 2\ s$

$v_f=20\ m/s$

The final velocity is 20 m/s.

8 0

3 years ago

Jesse wants to know how well a particular brand of car wax protects his car from dirt. What is the independent variable ?

miv72 [106K]

The brand of car wax

4 0

3 years ago

If τ=r×F then F.τ is equal

Mademuasel [1]

Yes that is correct.

4 0

3 years ago

A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.69 m above the bottom of the chute with

Veseljchak [2.6K]

Answer:

x = 6.94 m

Explanation:

For this exercise we can find the speed at the bottom of the ramp using energy conservation

Starting point. Higher

Em₀ = K + U = ½ m v₀² + m g h

Final point. Lower

$Em_{f}$ = K = ½ m v²

Em₀ = Em_{f}

½ m v₀² + m g h = ½ m v²

v² = v₀² + 2 g h

Let's calculate

v = √(1.23² + 2 9.8 1.69)

v = 5.89 m / s

In the horizontal part we can use the relationship between work and the variation of kinetic energy

W = ΔK

-fr x = 0- ½ m v²

Newton's second law

N- W = 0

The equation for the friction is

fr = μ N

fr = μ m g

We replace

μ m g x = ½ m v²

x = v² / 2μ g

Let's calculate

x = 5.89² / (2 0.255 9.8)

x = 6.94 m

6 0

3 years ago

Read 2 more answers