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kakasveta [241]
3 years ago
5

Which of the following statements are true? Check all that apply.

Physics
1 answer:
lidiya [134]3 years ago
8 0

We have 6 levels and we will verify which of them is true.

<em>A ) Electric charge is conserved </em>

According to the conservation of charge, an electric charge can neither be created nor be destroyed.

Therefore this statement is TRUE.

<em>B ) A positive charge and negative charge attract each other</em>

According to the properties of charges, the opposite charges attract each other and similar charges repel each other

Therefore this statement is  TRUE

<em>C) Two positive charges attract each other.</em>

Using the previous law, we can observe that this statement is false, because equal charges repel each other.

Therefore this statement is FALSE.

<em>D ) Two negative charges repel each other.</em>

Using the same principle as the two previous statements, two equal charges repel each other.

Therefore this statement is TRUE

<em>E) Electric charge is quantized.</em>

According to the quantization of charge, charges can take values only in integral multiples of a fundamental unit of charge.

Therefore this statement is TRUE.

<em>F) A neutral object contains no charge.</em>

A neutral object contains equal amount of negative and positive charge. Thus, in totality a neutral object contains no charge.

Therefore this statement is TRUE.

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Two geological field teams are working in a remote area. A global positioning system (GPS) tracker at their base camp shows the
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Answer:

distance of 2nd team from 1st team will be:  58.2

Direction of 2nd team from 1st team will be:  14.90 deg North of east

Explanation:

ASSUME Vector is R and  makes angle A with +x-axis,

therefore component of vector R is

R_x = Rcos A

R_y = Rsin A

From above relation

Assuming base camp as the origin, location of 1st team is

R_1 = 37 km away at 21 deg North of west (North of west is in 2nd quadrant, So x is -ve and y is positive)

R_{1x} = -R_1*cos A_1 = -37*cos 21 deg = -34.54 km

R_{1y} = R_1*sin A_1 = 37*sin 21 deg = 13.25 km

location of 2nd team is at

R_2 = 32 km, at 38 deg East of North = 32 km, at 58 deg North of east (North of east is in 1st quadrant, So x and y both are +ve)

R_{2x} = R_2*cos A_2 = 32*cos 58 deg = 16.95 km

R_{2y} = R_2*sin A_2 = 32*sin 58 deg = 27.13 km

Now position of 2nd team with respect to 1st team will be given by:

R_3 = R_2 - R_1

R_3 = (R_{2x} - R_{1x}) i + (R_{2y} - R_{1y}) j

Using above values:

R_3 = (16.95 - (-34.54)) i + (27.13 - 13.42) j

R_3 = 51.49 i + 13.71 j

distance of 2nd team from 1st team will be:

\left | R_3 \right | = \sqrt (51.49^2 +13.71^2)

\left | R_3 \right | = 53.28 km = 58.2 km

Direction of 2nd team from 1st team will be:

Direction = tan^{-1} \frac{R_{3y}}{R_{3x}} = tan^{-1}[ \frac{13.71}{51.49}]

Direction = 14.90 deg North of east

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In a physics laboratory experiment, a coil with 200 turns enclosing an area of 13.1 cm2 is rotated during the time interval 3.10
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Answer:

A)\Phi=83.84\times 10^{-9}

B)\Phi=0 Wb

C)emf=5.4090\times 10^{-4}V

Explanation:

Given that:

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  • area of the coil, a=13.1 \times 10^{-4}\,m^2
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Initially the coil area is perpendicular to the magnetic field.

So, magnetic flux is given as:

\Phi=B.a\,cos \theta..................................(1)

\theta is the angle between the area vector and the magnetic field lines. Area vector is always perpendicular to the area given. In this case area vector is parallel to the magnetic field.

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In this case the plane area is parallel to the magnetic field i.e. the area vector is perpendicular to the magnetic field.

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\Phi=6.4\times 10^{-5}\times 13.1 \times 10^{-4}\, cos 90^{\circ}

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(C)

According to the Faraday's Law we have:

emf=n\frac{B.a}{t}

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emf=5.4090\times 10^{-4}V

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Explanation:

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