Hi there!
The period of an orbit can be found by:
![T = \frac{2\pi r}{v}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%20r%7D%7Bv%7D)
T = Period (? s)
r = radius of orbit (6400000 m)
v = speed of the satellite (8000 m/s)
This is the same as the distance = vt equation. The total distance traveled by the satellite is the circumference of its circular orbit.
Let's plug in what we know and solve.
![T = \frac{2\pi (6400000)}{8000} = \boxed{5026.55 s}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%20%286400000%29%7D%7B8000%7D%20%3D%20%5Cboxed%7B5026.55%20s%7D)
Yes , increased tension suggests increased molecular attraction between the molecules of the ropes which affect the increase in the speed of wave.
Answer:
weight = 25*10 =250 N
Explanation:
g must be given in units of m/s^2
The weight of any type of body will be the product of his mass by the gravity
where:
m =mass [kg]
F = force [N] or [kg*m/s^2]
g = acceleration [m/s^2]
Answer:
![6.63\times 10^8\ N/C](https://tex.z-dn.net/?f=6.63%5Ctimes%2010%5E8%5C%20N%2FC)
Explanation:
Given that,
The magnitude of magnetic field, B = 2.21
We need to find the magnitude of the electric field. Let it is E. So,
![\dfrac{E}{B}=c\\\\E=Bc](https://tex.z-dn.net/?f=%5Cdfrac%7BE%7D%7BB%7D%3Dc%5C%5C%5C%5CE%3DBc)
Put all the values,
![E=2.21\times 3\times 10^8\\\\=6.63\times 10^8\ N/C](https://tex.z-dn.net/?f=E%3D2.21%5Ctimes%203%5Ctimes%2010%5E8%5C%5C%5C%5C%3D6.63%5Ctimes%2010%5E8%5C%20N%2FC)
So, the magnitude of the electric field is equal to
.
Answer:
1070 Hz
Explanation:
First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:
The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength
.
Hence, we have
![\dfrac{\lambda}{2}=58.5-42.5=16 \text{ cm}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Clambda%7D%7B2%7D%3D58.5-42.5%3D16%20%5Ctext%7B%20cm%7D)
.
The speed of a wave is the product of its wavelength and its frequency.
![v=f\lambda](https://tex.z-dn.net/?f=v%3Df%5Clambda)
![f=\dfrac{v}{\lambda}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7Bv%7D%7B%5Clambda%7D)
![f=\dfrac{343}{0.32}=1070 \text{ Hz}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B343%7D%7B0.32%7D%3D1070%20%5Ctext%7B%20Hz%7D)