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4 years ago

Which area of this sound wave represents a compression? A) B) C) D)

Physics

2 answers:

bekas [8.4K]4 years ago

8 0

C......................................

Evgesh-ka [11]4 years ago

4 0

'C' and 'E' are compressions.
'A' and 'D' are rarefactions.

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The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground

Elodia [21]

We know, s = ut + 1/2gt²
In free-fall, u = 0
so, t = √2s/g

Now, substitute the values,
t = √2*4 / 9.8 [ -ve sign shows opposite direction only ]
t = √8/ 9.8
t = 0.90 sec

In short, Your Answer would be 0.90 sec

Hope this helps!

8 0

4 years ago

Read 2 more answers

Which statement correctly describes the difference between an atom and a molecule

Alisiya [41]

Answer:

In a molecule, atoms are bonded together by single, double, or triple bonds. An atom has a nucleus surrounded by electrons.

Explanation:

3 0

3 years ago

Two cars are moving. The first car has twice the mass of the second car but only half as much kinetic energy. When both cars inc

Zanzabum

Answer:

20 mi

Exp3tanation:

I did the same question in a quizz

8 0

3 years ago

Light shines through a single slit whose width is 5.6 × 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a

Mrac [35]

Answer:

462 nm

Explanation:

Given: width of the slit, d = 5.6 × 10⁻⁴ m

Distance of the screen, D = 4.0 m

Fringe width, β = 3.3 mm = 3.3 × 10⁻³ m

First dark fringe means n =1

Wavelength of the light, λ = ?

$\beta = \frac{\lambda D}{d}\\ \Rightarrow \lambda = \frac{d \beta}{D} =\frac{5.6\times 10^{-4} \times 3.3 \times 10^{-3}}{4.0} = 4.62 \times 10^{-7}m = 462 nm$

5 0

3 years ago

Consider that a clay model of a tiger has a mass of 0.195 kg and glides on ice at a speed of 0.75 m/s. It hits another clay mode

juin [17]

Answer:

The final velocity after the collision is 0.27 m/s.

Explanation:

Given that,

Mass of tiger, m = 0.195 kg

Initial speed of tiger model, v = 0.75 m/s

Mass of another clay model, m' = 0.335 kg

Initially, second model is at rest, v' = 0

We need to find the final velocity after the collision. It is a case of inelastic collision. Using the conservation of linear momentum as :

$mv+m'v'=(m+m')V\\\\V=\dfrac{mv+m'v'}{(m+m')}\\\\V=\dfrac{0.195\times 0.75}{(0.195 +0.335 )}\\\\V=0.27\ m/s$

So, the final velocity after the collision is 0.27 m/s.

6 0

4 years ago