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jasenka [17]
3 years ago
8

1. Rocky lifted a 300 newton rock 2 meters off the ground and carried it 2 -

Physics
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer: 1200 joules

Explanation:

Work is done when force is applied on an object over a distance. It is measured in joules.

Thus, Work = Force X Distance

Since Force = 300 newton

Total distance = (distance off the ground + distance travelled on the ground)

i.e 2 meters off + 2 more meters = 4metres

Work = Force X Distance

= 300 Newton X 4 metres

= 1200 joules

Thus, Rocky did 1200 joules of work on the

rock

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if we are walking on a perfectly smooth ground which has no friction our force would simply cancel out the force reverted by the ground and we would fall.

We need it to help push out feet off the ground

Hope those helps :)

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Anaerobic metabolism:
goblinko [34]

Explanation:

B. leads to muscle strain.

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An object at 27°C has its temperature increased to 37°C.
Firlakuza [10]

Answer:

b. 14

Explanation:

T_{i} = Initial temperature = 27 °C = 27 + 273 = 300 K

T_{f} = Final temperature = 37 °C = 37 + 273 = 310 K

P_{i} = Initial Power radiated by the object

P_{f} = Final Power radiated by the object

We know that the power radiated is directly proportional to fourth power of the temperature. hence

\frac{P_{f}}{P_{i}} = \frac{T_{f}^{4} }{T_{i}^{4} }\\\frac{P_{f}}{P_{i}} = \frac{(310)^{4} }{(300)^{4} }\\\frac{P_{f}}{P_{i}} = 1.14\\P_{f} = (1.14) P_{i}

Percentage increase in power is given as

\frac{(P_{f} - P_{i})\times100}{P_{i}} \\\frac{((1.14) P_{i} - P_{i})\times100}{P_{i}} \\14

3 0
3 years ago
Diagnostic ultrasound of frequency 3.82 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such
maxonik [38]

Explanation:

It is given that,

Frequency of diagnostic ultrasound, f = 3.82 MHz = 3820 Hz

The speed of the sound in air, v = 343 m/s

(a) We need to find the wavelength in air of such a sound wave. Let it is given by λ₁

i.e. \lambda=\dfrac{v}{\nu}

\lambda_1=\dfrac{343\ m/s}{3820\ Hz}

\lambda_1=0.089\ m

(b) If the speed of sound in tissue is 1650 m/s .

\lambda_2=\dfrac{v}{\nu}

\lambda_2=\dfrac{1650\ m/s}{3820\ Hz}

\lambda_2=0.43\ m

Hence, this is the required solution.

7 0
3 years ago
Jerome is learning how the model of the atom has changed over time as new evidence was gathered. He has images of four models of
Stolb23 [73]

Answer:

Y, X, Z, W

Explanation:

You know W is the most recent because it features the nucleus in the middle and the electron cloud which was shown in models after the others.

5 0
3 years ago
Read 2 more answers
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