Answer:
How many grams of potassium chloride, KCl, must be dissolved in 500.0 mL of solution to produce a 1.5 M solution? Answer: g 4. What is the molarity of a solution in which 84.0 grams of sodium chloride, NaCl, is dissolved in 1.25 liters of solution? Answer: M 5.
Explanation:
Answer:
picograms
Explanation:
Please see attached picture for full solution.
The electronic configuration of x, y, and z.



<h3>What is an electronic configuration?</h3>
Electronic configuration, also called electronic structure, is the arrangement of electrons in energy levels around an atomic nucleus.
a.



b.
x= Period 1 and group18
Y=Element is in period 3 and Group 2
Z=Element is in period 3 and group 17.
c.
X, Y & Z represents Helium, magnesium, and chlorine.
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<u>Answer:</u> The chemical equations are written below.
<u>Explanation:</u>
<u>For a:</u> Methane reacts with oxygen gas to produce carbon dioxide and water.
Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water
The chemical equation for the combustion of methane follows:

- <u>For b:</u> Butane reacts with oxygen gas to produce carbon dioxide and water.
This is also an example of combustion reaction.
The chemical equation for the combustion of butane follows:

- <u>For c:</u> An aqueous solution of sulfuric acid reacts with aqueous potassium hydroxide to produce potassium sulfate and water.
When an acid reacts with a base, it leads to the formation of salt and water. This reaction is known as neutralization reaction
The chemical equation for the reaction of potassium hydroxide and sulfuric acid follows:

Hence, the chemical equations are written above.
Answer:
E = 3.81×10 ⁻²¹ J
Explanation:
Given data:
Frequency of photon = 5.75 ×10¹² Hz
Plancks constant = 6.626 ×10⁻³⁴ Js
Energy of photon = ?
Solution:
E = h×f
E = 6.626 ×10⁻³⁴ Js × 5.75 ×10¹² s⁻¹
E = 38.1×10 ⁻²² J
E = 3.81×10 ⁻²¹ J