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olga55 [171]
3 years ago
11

A chemist reacted 11.50 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is show

n.
Na + Cl2 → NaCl

If the percentage yield of the reaction is 85%, what is the actual yield? Show your work, including the use of stoichiometric calculations and conversion factors.

Will give brainlist for good job
Chemistry
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

24.65 grams Actual Yield

Explanation:

Given          2Na    +    Cl₂  =>        2NaCl

           11.50g/23g/mol

              = 0.50mole Na ----->  0.50mole NaCl Theoretical

                                               = 0.50mole NaCl x 58 g/mole

                                               = 29g NaCl Theoretical

Actual Yield = 85% of Theoretical Yield

                     = 0.85 x 29 grams

                     = 24.65 grams Actual Yield

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Lerok [7]

Answer:

<h2>0.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.01 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{3.01}{6.02}  \\  = 0.5

We have the final answer as

<h3>0.5 moles</h3>

Hope this helps you

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How many molecules are in 42.3g sample of water
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Answer:

The number of molecules is 1.4140*10^24 molecules

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To know the number of molecules, we need to determine how many moles of water we have, water has molar mass of 18.015g/mol

This means that one mole of water molecules has a mass of 18.015g.

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We are using avogadros number to find the number of molecules of water

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That's 2.3480 multiplied by 6.022*10^23 divided by 1 mole of H2O

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