Simple 6L of air times the .21L of O2 = 1.26
Yosef's hypothesis could be:
The larger the width of a rubber band, the harder it is to stretch it.
<u>Answer:</u> The molar mass of the unknown protein is 6387.9 g/mol
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
![\pi=iMRT](https://tex.z-dn.net/?f=%5Cpi%3DiMRT)
or,
![\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT](https://tex.z-dn.net/?f=%5Cpi%3Di%5Ctimes%20%5Cfrac%7B%5Ctext%7BMass%20of%20solute%7D%5Ctimes%201000%7D%7B%5Ctext%7BMolar%20mass%20of%20solute%7D%5Ctimes%20%5Ctext%7BVolume%20of%20solution%20%28in%20mL%29%7D%7D%5Ctimes%20RT)
where,
= osmotic pressure of the solution = 0.0766 atm
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of protein = 100. mg = 0.100 g (Conversion factor: 1 g = 1000 mg)
Molar mass of protein = ?
Volume of solution = 5.00 mL
R = Gas constant = ![0.0821\text{ L atm }mol^{-1}K^{-1}](https://tex.z-dn.net/?f=0.0821%5Ctext%7B%20L%20atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D)
T = temperature of the solution = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
Putting values in above equation, we get:
![0.0766atm=1\times \frac{0.100\times 1000}{\text{Molar mass of protein}\times 5}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 298K\\\\\pi=\frac{1\times 0.100\times 1000\times 0.0821\times 298}{0.0766\times 5}=6387.9g/mol](https://tex.z-dn.net/?f=0.0766atm%3D1%5Ctimes%20%5Cfrac%7B0.100%5Ctimes%201000%7D%7B%5Ctext%7BMolar%20mass%20of%20protein%7D%5Ctimes%205%7D%5Ctimes%200.0821%5Ctext%7B%20L.%20atm%20%7Dmol%5E%7B-1%7DK%5E%7B-1%7D%5Ctimes%20298K%5C%5C%5C%5C%5Cpi%3D%5Cfrac%7B1%5Ctimes%200.100%5Ctimes%201000%5Ctimes%200.0821%5Ctimes%20298%7D%7B0.0766%5Ctimes%205%7D%3D6387.9g%2Fmol)
Hence, the molar mass of the unknown protein is 6387.9 g/mol
Answer:
- <em>The element that makes up all organic compounds </em><u>is carbon (C)</u>
Explanation:
The term organic matter refers to the matter in the living organisms. Nowadays, organic compounds, the object of organic chemistry, are the compounds that contain carbon except carbon oxides, carbides and carbonates (which are considered inorganic compounds).
Organic compounds form a vast variety of vital compounds based on the versatility of carbon atoms.
Carbon atoms have four valence electrons which can form a variety of single, double, and triple bonds with it self, to form long chains.
Carbon atoms can also form bonds with other elements like, hydrogen, oxygen, nitrogen, halogens, among others, to form different kind of compounds: alkanes, alkenes, alkynes, alcohols, aldehydes, esters, eters, amines, amides, polymers, among others.
Thus, organic compounds form a vast subject of study based on the special chemical properties of carbon.