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krek1111 [17]
3 years ago
7

You have 75.0 mL of a 2.50 M solution of Na2CrO4(aq). How many mL of a 1.74 M solution of AgNO3(aq) are needed to completely rea

ct both reactants?
Chemistry
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

215 mL of silver nitrate are needed.

Explanation:

Let's think the reaction:

Na₂CrO₄(aq) + 2AgNO₃(aq) → Ag₂CrO₄ (s) ↓ + 2NaNO₃(aq)

First of all, we determine the moles of chromate we have available.

Molarity = mol / volume(L)

We convert volume to L → 75mL . 1L / 1000mL = 0.075 L

Molarity . volume(L) = moles → 2.50 M . 0.075L = 0.1875 moles

Ratio is 1:2. For 1 mol of chromate I need the double of moles of nitrate.

So, for 0.1875 moles of chromate I would need (0.1875 . 2) = 0.375 moles of nitrate. Let's determine volume of solution

Molarity = mol/ volume(L) → volume (L) = mol / Molarity

volume (L) = 0.375mol / 1.74M → 0.215L

We convert the value to mL → 0.215L . 1000mL/ 1L = 215 mL

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How many electrons does an element have if its atomic number is 20
olga55 [171]

Answer:

20 electrons

A neutral atom with atomic number 20 will have 20 electrons.

The atomic number is, by definiton, the number of protons in an atom's nucleus but for a neutral atom it's also equal to the number of electrons. Each element has a different, unique number of protons that determines its identity.

Explanation:

6 0
2 years ago
When a 2.00 g sample of KCl is dissolved in water in a calorimeter that has a total heat capacity of 1.28 kJ ⋅ K − 1 , the tempe
Alchen [17]

Answer : The molar heat of solution of KCl is, 17.19 kJ/mol

Explanation :

First we have to calculate the heat of solution.

q=c\times (\Delta T)

where,

q = heat produced = ?

c = specific heat capacity of water = 1.28kJ/K

\Delta T = change in temperature = 0.360 K

Now put all the given values in the above formula, we get:

q=1.28kJ/K\times 0.360K

q=0.4608kJ=460.8J

Now we have to calculate the molar heat solution of KCl.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 460.8 J

m = mass of KCl = 2.00 g

Molar mass of KCl = 74.55 g/mol

\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}=\frac{2.00g}{74.55g/mole}=0.0268mole

Now put all the given values in the above formula, we get:

\Delta H=\frac{460.8J}{0.0268mole}

\Delta H=17194.029J/mol=17.19kJ/mol

Therefore, the molar heat of solution of KCl is, 17.19 kJ/mol

7 0
3 years ago
You decided you want to make spaghetti for supper. You first light the gas stove because you need to cook the meat. When the mea
zloy xaker [14]

Answer:

C

Explanation:

Brainliest

7 0
3 years ago
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balance the following reaction. a coefficient of "1" is understood. choose option "blank" for the correct answer if the coeffici
suter [353]

Balanced chemical reaction: 2KCl + Pb(NO₃)₂ → PbCl₂ + 2KNO₃.

According to principle of mass conservation, number of atoms must be equal on both side of balanced chemical reaction.  

KCl is potassium chloride.

Pb(NO₃)₂ is lead(II) nitrate.

KNO₃ is potassium nitrate.

PbCl₂ is lead(II) chloride.

3 0
3 years ago
Which electron configuration represents the electrons of an atom in an excited state? * 2-3 2-7-1 2-8 2-8-1​
Lemur [1.5K]

2-7-1

<h3>Further explanation </h3>

Electrons can move the shell up or down by releasing energy or absorbing energy  

Excited electrons show higher electron transfer to the shell by absorbing energy  

So it can be concluded that there are 2 conditions:  

Ground state is the state of electrons filling shell with the lowest energy levels.  

Excited state is the state of electrons which occupies a higher energy level  

The state of excited electrons can be seen from the presence of electrons which do not fill the skin completely but fill the skin afterward  

2-7-1

From its 8 electron configuration, filling 3 shells, 2 electrons in the firs shell, 7 electrons in the second shell and 1 electron in the third shell

the electrons in the third shell should fill the electrons in the second shell first according to Aufbau rule (lower energy shells)

\tt  1s^22s^22p^4\rightarrow ground~state\\\\1s^22s^22p^33s^1\rightarrow excited~state

8 0
3 years ago
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