What is the osmolarity of a 0.20 M solution of KCI?
1 answer:
Answer:
Osmolarity of solution of KCI = 0.40 osmol
Explanation:
Given:
KCL ⇒ K⁺ + Cl⁻
Find:
Osmolarity of solution of KCI
When M = 0.20 M
Computation:
1 mole of KCL = 2 osmol
1 M of KCl = 2 Osmolarity
So,
Osmolarity of solution of KCI = 2 × 0.20
Osmolarity of solution of KCI = 0.40 osmol
You might be interested in
Can u repost with answer choices?
Molecular weight of AgBr = 187.7
moles of Ag =
moles of Br = moles of Ag = 2.96 x 10⁻³ mol
concentration of HBr (Molarity) = conc. of Br (strong acid) =
Answer: IT'S MUTATION I TOOK THE TEST ITS RIGHT HOPE THIS HELPED :)
Answer:
I think A close to the equator
Answer:
d d d d d d d d d dd d d d d .
f q q q q q