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3 years ago

What is she asking I am very confused

Chemistry

2 answers:

sashaice [31]3 years ago

8 0

Answer:

to me shes saying that you must read you vocab before reading your 6 paragraph article, then when you read that you will awnser some questions and they will all be in a student handout?

i kinda dont understand its confusing

Explanation:

Luden [163]3 years ago

7 0

Answer: Complete in order

1. Define key vocab words

2. Read the 6 paragraph article

3. Answer Higher Level Thinking questions

Explanation:

1. Give a very short definition for the vocab words (couple of words or less) but still try to remember the whole original definition

- make sure it makes sense to you

2. Read quickly (skim) the article and highlight or circle vocab words

-pay attention to the first and last sentence of each paragraph

- Go back and read the article more closely

- After each paragraph, write in one sentence something you learned or think is important (take-away sentence)

- Tell someone each of your take-away sentences and get their feedback ( do they agree or disagree?)

3. Answer the questions thoughtfully (put time into them)

- Long, thought out answers

- Use your knowledge of the article to answer them

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Someone pls help me I will mark you as brain

gavmur [86]

Answer:

1st one is the answer water cannot be purified by nature pls add me in brainliest

4 0

2 years ago

Theoretically, what mass of [Co(NH3)4(H2O)2]Cl2 could be produced from 4.00 g of CoCl2•6H2O starting material. If 1.20 g of [Co(

Romashka [77]

Answer: The theoretical yield and percent yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ is 3.93 g and 30.53 % respectively

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CoCl_2.6H_2O$ = 4.00 g

Molar mass of $CoCl_2.6H_2O$ = 238 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CoCl_2.6H_2O=\frac{4.00g}{238g/mol}=0.0168mol$

The chemical equation for the reaction of $CoCl_2.6H_2O$ to form $[Co(NH_3)_4(H_2O)_2]Cl_2$ follows:

$CoCl_2.6H_2O+4NH_3\rightarrow [Co(NH_3)_4(H_2O)_2]Cl_2+4H_2O$

By Stoichiometry of the reaction:

1 mole of $CoCl_2.6H_2O$ produces 1 mole of $[Co(NH_3)_4(H_2O)_2]Cl_2$

So, 0.0168 moles of $CoCl_2.6H_2O$ will produce = $\frac{1}{1}\times 0.0168=0.0168mol$ of $[Co(NH_3)_4(H_2O)_2]Cl_2$

Now, calculating the mass of $[Co(NH_3)_4(H_2O)_2]Cl_2$ from equation 1, we get:

Molar mass of $[Co(NH_3)_4(H_2O)_2]Cl_2$ = 234 g/mol

Moles of $[Co(NH_3)_4(H_2O)_2]Cl_2$ = 0.0168 moles

Putting values in equation 1, we get:

$0.0168mol=\frac{\text{Mass of }[Co(NH_3)_4(H_2O)_2]Cl_2}{234g/mol}\\\\\text{Mass of }[Co(NH_3)_4(H_2O)_2]Cl_2=(0.0168mol\times 234g/mol)=3.93g$

To calculate the percentage yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ , we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ = 1.20 g

Theoretical yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ = 3.93 g

Putting values in above equation, we get:

$\%\text{ yield of }[Co(NH_3)_4(H_2O)_2]Cl_2=\frac{1.20g}{3.93g}\times 100\\\\\% \text{yield of }[Co(NH_3)_4(H_2O)_2]Cl_2=30.53\%$

Hence, the theoretical yield and percent yield of $[Co(NH_3)_4(H_2O)_2]Cl_2$ is 3.93 g and 30.53 % respectively

6 0

3 years ago

10 points How many more oxygen atoms are in 3Mg3(PO4)2 than in 4Al2O3?

Feliz [49]

Answer:

12 more oxygen

Explanation:

An atom is the smallest particles that can take part in a chemical reaction

The given compounds are:

3Mg₃(PO₄)₂

Number of oxygen atoms = 3[2 x 4] = 24 oxygen atoms

For;

4Al₂O₃;

Number of oxygen atoms = 4 x 3 = 12 oxygen atoms

In 3Mg₃(PO₄)₂ , there are 24 - 12 = 12 more oxygen atoms than in 4Al₂O₃;

6 0

2 years ago

Read 2 more answers

Aluminum chloride, AlCl3, is an inexpensive reagent used in many industrial processes. It is made by treating scrap aluminum wit

mylen [45]

Answer:

83.8%

Explanation:

The balanced reaction equation is;

2Al(s) + 3Cl2(g) → 2AlCl3(s)

Now we have to obtain the limiting reactant as the reactant that produces the least amount of AlCl3

Amount of Al = 3.11g/27 g/mol = 0.115 moles

If 2 moles of Al yields 2 moles of AlCl3

Then 0.115 moles of Al yields 0.115 moles of AlCl3

For Cl2

Amount of Cl2 = 5.32 g/71 g/mol= 0.075 moles

If 3 moles of Cl2 yields 2 moles of AlCl3

0.075 moles of Cl2 yields 0.075 * 2/3 = 0.05 moles of AlCl3

Hence Cl2 is the limiting reactant

Theoretical yield of AlCl3 = 0.05 moles of AlCl3 * 133g/mol = 6.65 g

%yield = actual yield /theoretical yield * 100

%yield = 5.57 g/6.65 g * 100

%yield = 83.8%

4 0

2 years ago

How many grams of diphosphorus pentoxide result if 100.0 g of phosphorus are combined with sufficient oxygen?

gregori [183]

Answer is: 230 g.
Chemical reaction: P₄ + 5O₂ → 2P₂O₅.
m(P₄) = 100 g.
M(P₄) = 4 · 31 g/mol = 124 g/mol.
n(P₄) = m(P₄) ÷ M(P₄) = 100g ÷ 124g/mol = 0,806 mol.
From reaction: n(P₄) : n(P₂O5) = 1 : 2.
n(P₂O₅) = 1,612 mol.
m(P₂O₅) = 1,612 mol · 142g/mol = 230g.
M - molar mass.
n - amount of substance.

3 0

3 years ago