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kozerog [31]
3 years ago
7

When methane is burned with oxygen the products are carbon dioxide and water. if you produce 36 grams of water and 44 grams of c

arbon dioxide from 16 grams of methane, how many grams of oxygen were needed for the reaction?
Chemistry
1 answer:
seraphim [82]3 years ago
6 0
First of all we need to convert the masses to moles so that we can see the ratios of what we have been given.

36 grams of water divided by its molecular weight (18g/mol) gives us 2 moles of water.

44 grams of carbon dioxide divided by its molecular weight (44g/mol) is 1 mole of carbon dioxide. 

16 grams of methane divided by its molecular weight (16 grams) is 1 mole of methane.

We can look at a balanced chemical equation of methane burning such as the one below to find how much oxygen we need:

CH₄ + 2O₂ ⇒ CO₂ + 2H₂O

Therefore to burn one mole of methane we need two moles of oxygen molecules to produce one mole of carbon dioxide and two moles of water molecules. Because the amounts of water, methane and carbon dioxide in this equation match the ones we were given, we can say that 2 moles of oxygen molecules were required.

To convert this to grams we need to know the molecular weight of oxygen molecules, not atoms. By looking at a table of values you can see it is 32g/mol. Therefore two have two moles of oxygen molecules we need 64 grams of oxygen, which is the answer. 
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20 N force moving a box to 30 meters distance. How much work id done? if it takes 10 sec to do this work, how much power is used
dalvyx [7]

Answer:

Work done = 600 J

Power used = 60 W

Explanation:

Given:

Force acting on the box is, F=20\ N

Displacement of the box is, S=30\ m

Time taken for the work, t=10\ s

Now, we know that, work is said to be done by a force only when there is displacement caused by the force in its direction.

Here, the force acting on the box causes a displacement of 30 m in its direction. So, work done is equal to the product of force and displacement caused.

Therefore, work done on the box is given as:

Work=Force\times Displacement\\Work=F\times S\\Work=(20\ N)\times (30\ m)\\Work=600\ J

Therefore, the work done is 600 J.

Now, we know that, power is given as work done per unit time.

So, power used is given as:

Power=\frac{Work}{Time}\\\\Power=\frac{600\ J}{10\ s}\\\\Power=60\ W

Therefore, the power used is 60 W.

5 0
3 years ago
Potassium chlorate (used in fireworks, flares, and safety matches) forms oxygen and potassium chloride when heated. KClO3(s) → K
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Answer:

10.3 g of oxygen are formed when 26.4 g of potassium chlorate is heated

Explanation:

This is the balanced equation:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

Ratio beteween the salt and oxygen is 2:3

Molar mass of KClO₃ = 122.55 g/m

Let's find out the moles of salt

Mass / Molar mass

26.4 g /122.55 g/m = 0.215 moles

So, this is the final rule of three:

If 2 moles of KClO₃ make 3 moles of oxygen

0.215 moles of KClO₃ make  (0.215  .3) /2 = 0.323 moles of O₂ are produced

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Moles . molar mass = mass

0.323 m  . 32g/m = 10.3 g

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The density of solid Cr is 7.15 g/cm3. How many atoms are present per cubic centimeter of Cr?
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