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Nataly [62]
3 years ago
6

You spin the spinner twice.

Mathematics
1 answer:
Pavel [41]3 years ago
3 0

Answer:

The Answer is 1 and 4

Step-by-step explanation:

Because there is only 4 numbers.

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Find an equation for the graph below
RoseWind [281]

Answer:

y=4/5x-0.8

Step-by-step explanation:

7 0
3 years ago
Does the line passing through the points (3, 3) and (7, 11) intersect the line passing through the points (5, 8) and (13, 24
victus00 [196]

Answer:

I understand why you are asking about this Ammaria, these type of questions take a lot of understanding of graphing.  Please feel ok asking me questions :)

Step-by-step explanation:

we are given two points

P1 = (3,3)  in the form (x1,y1)

P2 = (7,11) in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

m = (11-3) / (7-3)

m = 8 / 4

m = 2

now use the slope along with one of the given points, either one will work, i'll use P1 , and put that into the point-slope formula.

y-3 = 2(x-3)

y -3 = 2x -6

y = 2x -3

So with the above formula we can check to see if the points work by plugging them into the formula.  

P3 = (5,8)

8 = 2(5) - 3

no point 3 does not work so it's not on the line

P4 = (13, 24)

24 = 2(13) - 3

no point 4 does not work either.

7 0
3 years ago
X +11 -8 ÷ -2<br><br>I need help, it's a to step-equation!! ​
____ [38]

Answer:

x+7 oops x+15 ignore the first answer

Step-by-step explanation:

x+11-8/-2

first do -8/-2=4

so it is x+11+4

11+4

x+15 is the answer

pls brainliest

6 0
3 years ago
Read 2 more answers
When do u evaluate exponents in the order of operations?? <br> Pls help I got 9 minutes to do this
olga2289 [7]

Answer:

2nd

Step-by-step explanation:

Perenthasis

Exponets

Multiply

Divide

Add

Subtract

3 0
3 years ago
Construct a 99% confidthence interval for the population mean .Assume the population has a normal distribution. A group of 19 ra
Kobotan [32]
<h2>Answer with explanation:</h2>

Confidence interval for mean, when population standard deviation is unknown:

\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n= sample size

s= sample standard deviation

t_{\alpha/2} = Critical t-value for n-1 degrees of freedom

We assume the population has a normal distribution.

Given, n= 19 , s= 3.8 , \overline{x}=22.4

\alpha=1-0.99=0.01

A) Critical t value for \alpha/2=0.005 and degree of 18 freedom

t_{\alpha/2} = 2.8784

B) Required confidence interval:

22.4\pm ( 2.8744)\dfrac{3.8}{\sqrt{19}}\\\\=22.4\pm2.5058\\\\=(22.4-2.5058,\ 22.4+2.5058)=(19.8942,\ 24.9058)\approx(19.9,\ 24.9)

Lower bound = 19.9 years

Uppen bound = 24.9 years

C) Interpretation: We are 99% confident that the true population mean of lies in (19.9, 24.9) .

5 0
4 years ago
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