Question

complete and balance the molecular equation for the reaction of aqueous copper(II) chloride, CuCl2,CuCl2, and aqueous potassium phosphate, K3PO4.K3PO4. Include physical states. molecular equation: CuCl2(aq)+K3PO4(aq)⟶CuCl2(aq)+K3PO4(aq)⟶ Enter the balanced net ionic equation for this reaction. Include physical states.

Answer 1

Answer : The net ionic equation will be,

$3Cu^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Cu_3(PO_4)_2(s)$

Explanation :

First we have to balance the chemical reaction.

The given balanced ionic equation will be,

$3CuCl_2(aq)+2K_3PO_4(aq)\rightarrow Cu_3(PO_4)_2(s)+6KCl(aq)$

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The ionic equation in separated aqueous solution will be,

$3Cu^{2+}(aq)+6Cl^-(aq)+6K^+(aq)+2PO_4^{3-}(aq)\rightarrow Cu_3(PO_4)_2(s)+6K^+(aq)+6Cl^-(aq)$

In this equation, $K^+\text{ and }Cl^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$3Cu^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Cu_3(PO_4)_2(s)$