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AfilCa [17]
3 years ago
10

complete and balance the molecular equation for the reaction of aqueous copper(II) chloride, CuCl2,CuCl2, and aqueous potassium

phosphate, K3PO4.K3PO4. Include physical states. molecular equation: CuCl2(aq)+K3PO4(aq)⟶CuCl2(aq)+K3PO4(aq)⟶ Enter the balanced net ionic equation for this reaction. Include physical states.
Chemistry
1 answer:
oee [108]3 years ago
4 0

Answer : The net ionic equation will be,

3Cu^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Cu_3(PO_4)_2(s)

Explanation :

First we have to balance the chemical reaction.

The given balanced ionic equation will be,

3CuCl_2(aq)+2K_3PO_4(aq)\rightarrow Cu_3(PO_4)_2(s)+6KCl(aq)

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The ionic equation in separated aqueous solution will be,

3Cu^{2+}(aq)+6Cl^-(aq)+6K^+(aq)+2PO_4^{3-}(aq)\rightarrow Cu_3(PO_4)_2(s)+6K^+(aq)+6Cl^-(aq)

In this equation, K^+\text{ and }Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

3Cu^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Cu_3(PO_4)_2(s)

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3 years ago
In the reaction 2co ( g) + o2( g) → 2co2( g), what is the ratio of moles of oxygen used to moles of co2produced?
KIM [24]
In the reaction 2co ( g) + o2( g) → 2co2( g), the ratio of moles of oxygen used to moles of co2produced is 1:2.
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Why does burned toast taste so bad? Is it a chemical or physical change?
german

Because things that are burnt have been changed into something else like moldy bread thats cooked.

It is chemical change because you cannot unburn something.

4 0
3 years ago
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How many grams of sodium chloride are contained in 250.0 g of a 15% NaCl solution?
kramer

Given concentration of NaCl=15%

Means ,

In every 100g of Solution 15g of NaCl is present .

Now

  • Given mass=250g

So ,

\\ \Large\sf\longmapsto 250\times 15\%

\\ \Large\sf\longmapsto 250\times \dfrac{15}{100}

\\ \Large\sf\longmapsto 37.5g

<u>37.5g of NaCl present in 250g of solution.</u>

8 0
3 years ago
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A gas mixture at 535.0°C and 109 kPa absolute enters a heat exchanger at a rate of 67.0 m3/hr. The gas leaves the heat exchanger
SVEN [57.7K]

Answer:

the heat rate required to cool down the gas from 535°C until 215°C is -2.5 kW.

Explanation:

assuming ideal gas behaviour:

PV=nRT

therefore

P= 109 Kpa= 1.07575 atm

V= 67 m3/hr = 18.6111 L/s

T= 215 °C = 488 K

R = 0.082 atm L /mol K

n = PV/RT = 109 Kpa = 1.07575 atm * 18.611 L/s /(0.082 atm L/mol K * 488 K)

n= 0.5 mol/s

since the changes in kinetic and potencial energy are negligible, the heat required is equal to the enthalpy change of the gas:

Q= n* Δh = 0.5 mol/s * (- 5 kJ/mol) =2.5 kW

7 0
3 years ago
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