Answer:
2 mol of SO3 produces 1 mol O2
3 mol SO3 produces 3/2 mol of O2
so O2 produced = 1.5(32) =48 gm
Explanation:
Answer:
0.26g of NaCl is the maximum mass that could be produced
Explanation:
Based on the reaction:
HCl + NaOH → NaCl + H₂O
<em>Where 1 mol of HCl reacts per mol of NaOH to produce 1 mol of NaCl</em>
<em />
To solve this question we need to find <em>limiting reactant. </em>The moles of limiting reactant = Moles of NaCl produced:
<em>Moles HCl -Molar mass: 36.46g/mol-:</em>
0.365g HCl * (1mol / 36.46g) = 0.010 moles HCl
<em>Moles NaOH -Molar mass: 40g/mol-:</em>
0.18g NaOH * (1mol / 40g) = 0.0045 moles NaOH
As the reaction is 1:1 and moles NaOH < moles HCl, limiting reactant is NaOH and maximum moles produced of NaCl are 0.0045 moles.
The mass of NaCl is:
<em>Mass NaCl -Molar mass: 58.44g/mol-:</em>
0.0045 moles * (58.44g/mol) =
<h3>0.26g of NaCl is the maximum mass that could be produced</h3>
Answer:
Explanation:
From the given information:
Since 300 ml of intravenous infusion contains 300 mg of drugs;
Then; 1 ml of intravenous infusion contains (x) amount of drugs
(x) amount of drugs = (300 mg × 1 ml)/ 300 ml
(x) amount of drugs = 1 mg.ml
To calculate the drip rate in drops/minutes by applying conversion factors.
![rate (\dfrac{ in \ drops }{minute })= \dfrac{2 \ mg }{min } \times \dfrac{20 \ drops}{1 \ ml} \times \dfrac{1 \ ml }{1 \ mg }](https://tex.z-dn.net/?f=rate%20%28%5Cdfrac%7B%20in%20%5C%20drops%20%7D%7Bminute%20%7D%29%3D%20%5Cdfrac%7B2%20%5C%20mg%20%7D%7Bmin%20%7D%20%5Ctimes%20%5Cdfrac%7B20%20%5C%20drops%7D%7B1%20%5C%20ml%7D%20%5Ctimes%20%5Cdfrac%7B1%20%5C%20ml%20%7D%7B1%20%5C%20mg%20%7D)
![rate (\dfrac{ in \ drops }{minute }) = 40 \ drops / min](https://tex.z-dn.net/?f=rate%20%28%5Cdfrac%7B%20in%20%5C%20drops%20%7D%7Bminute%20%7D%29%20%3D%2040%20%5C%20%20drops%20%2F%20min)
Answer: they form a color called yellow-green
Explination: hard to explain just look it up on google or something
For this item, the <span>∆t will be the value of temperature difference that the substances will experience once subjected to same amount of heat. The heat is equal to,
H = mcp</span><span>∆t
where H is heat, m is mass, cp is specific heat, and </span><span>∆t is temperature difference.
The compounds given, despite having the almost the same molecular weight, will have different </span><span>∆t because of the different intermolecular forces present especially in the alkyl groups present. </span>