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3 years ago

Which of the following molecules contains six bonding electrons?

Chemistry

1 answer:

cestrela7 [59]3 years ago

8 0

Answer:

c2h4 (etthane........

bexcuse it has 6 bond of hydrogen

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If only 0.186 g of Ca(OH)2 dissolves in enough water to give 0.230 L of aqueous solution at a given temperature, what is the Ksp

Lilit [14]

Answer:

$Ksp=5.20x10^{-6}$

Explanation:

Hello there!

In this case, according to the solubility equilibrium of calcium hydroxide:

$Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-$

Whereas the equilibrium expression is:

$Ksp=[Ca^{2+}][OH^-]^2$

It is firstly necessary to calculate the molar solubility given the grams and volume of the dissolved solute:

$s=\frac{0.186g/(74.09g/mol)}{0.230L}=0.0109M$

Now, according to the Ksp expression, we plug in s as the solubility to obtain:

$Ksp=(s)(2s)^2\\\\Ksp=(0.109)(2*0.0109)^2\\\\Ksp=5.20x10^{-6}$

Regards!

8 0

3 years ago

Someone please help me with the second question ONLY

wlad13 [49]

Answer:

Explanation:

this experiment could not be replicated, because there are no specific measurements. the details would not be the same because it does not include the type of paper used nor the diameter, width or length. A guess of the measurements would be the only way to replicate this experiment but other then that, no you cannot.

4 0

3 years ago

1. (NH)2CrO-

Alex777 [14]

Question:

1. (NH)2CrO

a) Number of moles of H:

b) Number of moles of N:

Answer:

a) Number of moles of H: 2

b) Number of moles of N: 2

Explanation:

The $(NH)_2CrO$ is ammonium Chromate which is monoclinic and yellow Crystal that is formed due to the reaction of ammonium Hydroxide and ammonium di-chromate. It is used as catalyst, corrosion inhibitor as well as analytical inhibitors.

Question:

2. Ag.SO.

a) Molar Mass:

b) Percent Composition of Ag:

c) Percent Composition of S:

d) Percent Composition of O:

Answer:

a) Molar Mass: 155.93 Kg

b) Percent Composition of Ag: 69%

c) Percent Composition of S: 20.5%

d) Percent Composition of O: 10.2%

Explanation:

Molar mass = molar mass of Ag + molar mass of S + molar mass of O

=>107.87+32.06+16

=> 155.93 Kg

Percent Composition of Ag

= $\frac{ \text{mass due to Ag}}{\text {total molar mass}} \times 100$

= $\frac{107.87}{155.93} \times 100$

= 0.69 \times 100

= 69%

Percent Composition of S:

= $\frac{ \text{mass due to S}}{\text {total molar mass}} \times 100$

= $\frac{32.06}{155.93} \times 100$

= 0.205 \times 100

= 20.5%

Percent Composition of O:

= $\frac{ \text{mass due to O}}{\text {total molar mass}} \times 100$

= $\frac{16.00}{155.93} \times 100$

= 0.102 \times 100

= 10.2%

3 0

3 years ago

In tissue engineering, scaffolds are built for growing replacement body parts primarily so that:

Stels [109]

One of the functions of scaffolds in tissue engineering is letter b. cells grow into the correct shape. Scaffolds used in tissue engineering have biomaterials with biological attributes that will enhance cell attachment and topography where cells morph and align.

7 0

4 years ago

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Which alcohol will behave most like water? C2H5OHC4H9OHC10H21OHC7H15OH

mylen [45]

Which alcahol will behave most like water?
 C2H5OH
hope it helps

6 0

3 years ago

Read 2 more answers