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DaniilM [7]
3 years ago
7

When two forces acting on an object are equal, they are

Chemistry
1 answer:
TEA [102]3 years ago
7 0
The answer is balanced forces
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Suspect A is actually telling the truth and they describe the events of a certain evening with confidence. After being asked to
lorasvet [3.4K]

It seems like the answer is C, you really just need to use the process of elimination.

7 0
3 years ago
The point in a titration at which the indicator changes is called the
irakobra [83]

Answer:

End point

Explanation:

The point at which the indicator changes color is called the endpoint. So the addition of an indicator to the analyte solution helps us to visually spot the equivalence point in an acid-base titration

#correct me if I'm wrong

keep safe and study hard

brainliest please thank you

8 0
2 years ago
__________ have an electric charge of -1.60 × 10-19 C (-e).
nignag [31]

Answer:

Electrons have an electric charge of -1.60 × 10-19 C

Explanation:

Neutrinos and Neutrons have 0 e charge.

Protons have an electric charge of 1.60 × 10-19 C

Historically, electrons were assigned a negative charge

6 0
3 years ago
11. What is the specific heat of a substance with a mass of 25.5 g that requires 412 J
Romashka-Z-Leto [24]

Answer:

297 J

Explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

1

∘

C

.

In your case, aluminium is said to have a specific heat of

0.90

J

g

∘

C

.

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

1

∘

C

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

1

∘

C

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

1

∘

C

, you'd have to provide it with

1 gram



0.90 J

+

1 gram



0.90 J

+

...

+

1 gram



0.90 J



10 times

=

10

×

0.90 J

However, you don't want to increase the temperature of the sample by

1

∘

C

, you want to increase it by

Δ

T

=

55

∘

C

−

22

∘

C

=

33

∘

C

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

1

∘

C



10

×

0.90 J

+

1

∘

C



10

×

0.90 J

+

...

+

1

∘

C



10

×

0.90 J



33 times

=

33

×

10

×

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

33

∘

C

will be

q

=

10.0

g

⋅

0.90

J

g

∘

C

⋅

33

∘

C

q

=

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

q

=

m

⋅

c

⋅

Δ

T

, where

q

- the amount of heat added / removed

m

- the mass of the substance

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

6 0
3 years ago
Consider separate 1.0-L samples of He(g) and UF6(g), both at 1.00 atm and containing the same number of moles. What ratio of tem
diamong [38]
V =  \sqrt{x} 3 * R * T / MW

V = RMS velocity

R = 8.3145 J/K*mole

T = Temperature K

MW = Molecular weigh in Kg
3 0
3 years ago
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