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Juli2301 [7.4K]
3 years ago
13

Scientists gather information to understand why and where earthquakes happen. What is the name of the machine that helps them me

asure earthquake activity?
Chemistry
1 answer:
creativ13 [48]3 years ago
6 0
There are two scales, one is a Ritcher scale and another one is called a Mercalli scale.
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How many days pass until the exact same Moon shape reappears?
Troyanec [42]
22 because that how many days it will take for the exact moon shape to pass and it will then reappear.
4 0
3 years ago
Sodium-potassium pumps are examples of what type of cellular transport?
Dmitrij [34]

Answer:

Active transport

Explanation:

Sodium-potassium pumps are examples of Active type of cellular transport. Sodium potassium pump exchanges sodium ions from potassium ions through the plasma membrane of animal cells.

Whereas Active transport can be defined as movement of ions and molecules across a cell membrane to the region  of higher concentration with the help of enzymes and energy.

5 0
4 years ago
1. What would happen to the position of equilibrium when the following changes are made to the reaction below? 2Hg3O (g) ↔ 6Hg (
Mademuasel [1]
What is your answer I can help you)
4 0
3 years ago
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5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf
mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
3 years ago
What is the hydrogen ion concentration, [H+], of a solution with a pH of 5.43?
grigory [225]

Answer: 3.7 x10−6 Mole per dm^3

Explanation:

pH is the negative logarithm of hydrogen ion concentration in a solution.

So, pH = - log(H+)

Since the solution has a pH of 5.43

5.43 = -log(H+)

To get hydrogen ion concentration, find the Antilog of 5.43

(H+) = Antilog (-5.43)

(H+) = 0.000003715

Then, 0.000003715 in standard form becomes 3.7 x10−6 M

Thus, the concentration of hydrogen ion in the solution is 3.7 x10−6 Mole per dm^3

6 0
3 years ago
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