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kykrilka [37]
3 years ago
6

The air in a tire pump has a volume of 1.5 L at a temperature of 5 ℃. If the temperature is increased to 25 ℃ and the pressure r

emains constant, what is the new volume of the tire pump
Physics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

Explanation:

5 C = 278 K

25 C = 298 K

V1 / T1 = V2 / T2

1.5L / 278 K = V2 / 298 K

V2 = (1.5L * 298) / 278

V2 = 1.61 L

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Explanation:

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mass = m = 5kg

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