A hot–air balloon is moving at a speed of 10.0 meters/second in the +x–direction. The balloonist throws a brass ball in the +x–d
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The magnetic moment is -
M = 5.5 x A
.
We have current carrying single circular loop placed in a magnetic field
parallel to the plane of the loop.
We have to determine the Magnetic moment of the loop.
<h3>What is the formula to calculate the magnetic moment of loop?</h3>The formula to calculate the magnetic moment of the loop is -
M = NIA
where -
N - Number of turns
I - Current in the loop
A - Area of the loop
According to the question, we have -
I = 17mA = 0.017A
Circumference (C) = 2 meters
B = 0.8 T
Now -
C = 2
2r = 2
r = 1
r =
r = 0.32
Using the formula -
M = NIA
M = NI
M = 3.14 x 1 x 0.017 x 0.32 x 0.32
M = 3.14 x 4 x 0.017
M = 5.5 x A
Hence, the magnetic moment is -
M = 5.5 x A
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