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Allisa [31]
3 years ago
8

A hot–air balloon is moving at a speed of 10.0 meters/second in the +x–direction. The balloonist throws a brass ball in the +x–d

irection at a velocity of +4 meters/second with respect to himself. If the ball lands after 30 seconds, about how far does it land horizontally from the point at which it was released?
A. 120 meters
B. 125 meters
C. 300 meters
D. 420 meters
Physics
1 answer:
Ad libitum [116K]3 years ago
6 0

Answer:

Option (D) is correct.

Explanation:

The balloon lands horizontally at a distance of 420 m from a point where it as released.

Velocity of air balloon along +X axis =10 m/s

velocity of ball=4 m/s along + X axis

the velocity of balloon gets added to the velocity of ball. So the resultant velocity of the balloon=10+4 = 14 m/s

time taken= 30 s

The distance traveled is given by d= v t

d= 14 (30)

d= 420 m

Thus the balloon lands horizontally at a distance of 420 m from a point where it as released.

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How to do the equation p1v1 = p2v2 as an equation layed out like:
KonstantinChe [14]

P1 and P2 are the pressures, and V1 and V2 are the volumes. So you take the first pressure and volume you are given and place them into the equation P1V1 so the first part of the equation would be 101000*0.5 = P2V2. You then rearrange the equation to find what you want, in this instance you would do 50500/0.25 = P2... therefore P2 = 2020000Pa or 2.02*10^6Pa
4 0
3 years ago
Instruction Active
nikklg [1K]

If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects

<u>Answer:</u>

increases

Explanation:

The formula of gravitational force is given as:

F=G Mm/r^2

G = gravitational constant

M, m = Masses of two different objects in which the force is acting.

r = distance between both the objects.

As we can see from the formula that the force of gravity is inversely proportional to the square of the distance between both objects.

When the distance between both objects with the same masses decreases the gravitational force between them increases. Hence the correct answer is option B.

Illamends had the exact same answer from a similar question. Credit goes to her

4 0
2 years ago
Read 2 more answers
A fillet weld has a cross-sectional area of 25.0 mm2and is 300 mm long. (a) What quantity of heat (in joules) is required to acc
HACTEHA [7]

Answer:

77362.56 J

163730.28571 J

Explanation:

A = Area = 25 mm²

l = Length = 300 mm

K = Constant = 3.33\times 10^{-6}

\eta = Heat transfer factor = 0.75

f_m = Melting factor = 0.63

T = Melting point of low carbon steel = 1760 K

Volume of the fillet would be

V=Al\\\Rightarrow V=25\times 300\\\Rightarrow V=7500\ mm^3=7500\times 10^{-9}\ m^3

The unit energy for melting is given by

U_m=KT^2\\\Rightarrow U_m=3.33\times 10^{-6}\times 1760^2\\\Rightarrow U_m=10.315008\ J/mm^3

Heat would be

Q=U_mV\\\Rightarrow Q=10.315008\times 7500\\\Rightarrow Q=77362.56\ J

Heat required to weld is 77362.56 J

Amount of heat generation is given by

Q_g=\dfrac{Q}{\eta f_m}\\\Rightarrow Q_g=\dfrac{77362.56}{0.75\times 0.63}\\\Rightarrow Q_g=163730.28571\ J

The heat generated at the welding source is 163730.28571 J

7 0
4 years ago
Suppose you place a ball in the middle of a wagon, and then accelerate the wagon forward. Describe the motion of the ball relati
rjkz [21]

Answer:

The motion of the ball relative to the ground is stationary

The motion of the ball relative to the wagon is backwards

Explanation:

To describe the motion of the ball relative to the ground, we note that

Assuming the ball is perfectly round and rotate freely, then we have

Force on the ball due to motion of the wagon = 0 N,

Then by the law of motion, an object will remain at rest when no force is applied to it

Therefore, apart from rotation of the ball, it will remain no displacement relative to the ground.

The motion of the ball relative to the wagon

Relative to the wagon, the ball appears to be moving in the opposite direction to the wagon, that is backwards.

4 0
4 years ago
Read 2 more answers
A current of 0.86 a flows through a copper wire 0.47 mm in diameter when it is connected to a potential difference of 15 v. how
likoan [24]

To calculate the length of the wire, we use formulas,

R = \frac{V}{I}                                       (A)

R= \rho  \frac{l}{A}                                (B)

Here, R is the resistance of the wire, I is the current flows through wire and V is potential difference. A is cross sectional area of wire and \rho is the density of copper wire and is value,\rho = 1.7\times 10^{-8} \Omega m.

Given    I = 0.86 A,V=15 V and  r = \frac{0.47 mm}{2} =2.35 \times 10^{-4} m, V= 15 V.

Substituting the values of I and V in equation (A ) we get,

R=\frac{15V}{0.86A} = 17.44 \Omega

Now from equation (B),

l=\frac{R A}{\rho }

Therefore,

l= \frac{17.44\times\pi \times r^2  }{1.7\times 10^{8} \Omega m} \\\\ l= \frac{17.44\times 3.14 \times(2.35\times10^{-4}m)^2  }{1.7\times 10^{-8} \Omega m} = 177.9 m

Thus the length of the copper wire is 177.9 m.

8 0
3 years ago
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