Question

You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abort the landing, so he pulls up, moving in a semicircular upward-bending path. The path has a radius of 450m with a radial acceleration of 17m/s2. What is the plane’s speed?

Answer 1

Answer:

$v=87.46m/s$

Explanation:

Objects moving in circular path would be have either centripetal or centrifugal  force.The force is either to center or away from center. When the object is moving along the circular path the centripetal force is

$F=\frac{mv^{2}}{r}$

Here m is mass, v is velocity and r is radius of circular path

The acceleration is given by:

$a_{r}=\frac{v^{2}}{r}$

The point of interest is lowest point on circle.The acceleration of plane at  this position point up.The speed of plane from radial acceleration equation is:

$v=\sqrt{a.r}$

Substitute 17 m/s² for a and 450m for r

So

$v=\sqrt{17m/s^{2}*450m }\\ v=87.46m/s$