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Lerok [7]
3 years ago
6

what happens to the water after it rains? a. precipitation b. runoff c. condensation user: what do organisms from the ocean use

the carbon dioxide for? a. to breathe b. to build bones c. to make shells d. to help organisms decompose
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
The rain gets evaporated in to water vapor and is returned to the clouds where they go through condensation and then they poud down as rain or A.K.A,  Precipitation.
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A disk with a diameter of 0.05 m is spinning with a constant velocity about an axle perpendicular to the disk and running throug
Maksim231197 [3]

Answer:

f= 7.8Hz

Explanation:

a= 12g= 120m/s²

a= ω²r

120= ω²×0.05

ω= 48.99 rad/s

2πf= 48.99

f= 7.8Hz

8 0
3 years ago
What is the force on a person’s hand, which is using a rope to accelerate a 5 kg block upward with an acceleration of 2.2 m/s 2
slavikrds [6]

Answer:

F = 11 N

Explanation:

Given,

Mass of a block, m = 5 kg

Acceleration of the block, a = 2.2 m/s²

We need to find the force on the person's hand. Let it is F. We know that force is given by the product of mass and acceleration as follows :

F = ma

F = 5 kg × 2.2 m/s²

F = 11 N

So, the force on a person's hand is 11 N.

5 0
3 years ago
Here, mA = 3.65 kg and mB = 7.05 kg. The string connecting the two objects is of negligible mass and the pulley is frictionless.
mr_godi [17]

Answer:

The magintude of the acceleration for both objects is 3.11m/s^2

Explanation:

Drawing a free body diagram on the two boxes we can analyze the system more easily.

we can take the acceleration going up as positive for reference purposes.

for mA let's suppose that is ascending so:

T_A-m_A*g=m_A*a

and for mB (descending):

T_B-m_B*g=-m_B*a

T_A=T_B

because the two boxes has the same acceleration because they are attached together:

m_B*g-m_B*a-m_a*g=m_a*a\\(m_B-m_A)*g=(m_a+m_B)*a\\a=\frac{(7.05kg-3.65kg)*9.8m/s^2}{3.65kg+7.05kg}\\\\a=3.11m/s^2

So the magintude of the acceleration for both objects is 3.11m/s^2

5 0
3 years ago
A race car circles 10 times around a circular 8.0-km track in 20 min.
Otrada [13]
Find the average speed and the average velocity.

Average speed = distance / time

distance = 10 x 8000 m = 80,000 m
time = 20 min * 60 s/min = 1200 s

Average speed = 80,000 m / 1200 s = 66.67 m/s

Average velocity = displacement / time

Given that the race car made complete circles the final poin is the same initial point, then its displacement is zero and the average velocity is zero too.
6 0
3 years ago
Read 2 more answers
Light with a frequency of 7.30 x 1014 hz lies in the violet region of the visible spectrum. What is the wavelength of this frequ
Leona [35]

From the theory we know that:

c = λ / T

f = 1 / T

Where:

c = 3.10^{8} / m   (the speed of light)

λ is the wavelengh (in meters)

T is the period (in seconds)

f is the frequency (in Hz)

We were told that:

f = 7.30 . 10^{14}

And we want to find out the value of λ.

c = λ / T  

c = λ . 1/T

Swaping 1/T = f

c = λ . f

λ = c / f

λ = 3 . 10^{8} /  7.30 . 10^{14}

λ = 4.12 10^{-7} m

Response: 4.12 10^{-7} m = 412 nm

:-)

6 0
3 years ago
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