Given that the mass is m = 0.2 kg and the displacement is x = 3 cm = 0.03 m
We have to find the spring constant and potential energy.
The spring constant can be calculated by the formula
Here, k is the spring constant.
g = 9.8 m/s^2 is the acceleration due to gravity.
Substituting the values, the spring constant will be
The potential energy can be calculated as
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Explanation: Yw and mark me as brainiest
Assuming the objects roll down the inclined plane, yes.
If the object never touches the plane, then no.
Answer:
The magnitude of the acceleration of the elevator is 0.422 m/s²
Explanation:
Lets explain how to solve the problem
Due to Newton's Law ∑ Forces in direction of motion is equal to mass
multiplied by the acceleration
We have here two forces 460 N in direction of motion and the weight
of the person in opposite direction of motion
The weight of the person is his mass multiplied by the acceleration of
gravity
→ W = mg , where m is the mass and g is the acceleration of gravity
→ m = 45 kg and g = 9.8 m/s²
Substitute these values in the rule above
→ W = 45 × 9.8 = 441 N
The scale reads 460 N
→ F = 460 N , W = 441 N , m = 45 kg
→ F - W = ma
→ 460 - 441 = 45 a
→ 19 = 45 a
Divide both sides by 45
→ a = 0.422 m/s²
<em>The magnitude of the acceleration of the elevator is 0.422 m/s²</em>
F=ma
Velocity is Distance over time so Vf = 75/15 = 5m/s
Find acceleration V=Vo+at. plugging in the values you know, you get
0.33m/s^2
F=(2100)(0.33)=693N
