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Ksivusya [100]
3 years ago
6

4a.) A 0.50 kg water balloon is thrown against a wall at 32 m/s coming to a stop. What was its change in

Physics
1 answer:
pychu [463]3 years ago
7 0

Answer:

-16 kg m/s

Explanation:

Momentum is a vector quantity indicating the "amount of motion" in an object.

The change in momentum of an object is given by:

\Delta p = m(v-u)

where:

m is the mass of the object

u is its initial velocity

v is its final velocity

For the water balloon in this problem, we have:

m = 0.50 kg is the mass

u = 32 m/s is the initial velocity

v = 0 m/s (since the balloon comes to a stop)

Therefore, the change in momentum is:

\Delta p=(0.50)(0-32)=-16 kg m/s

And the negative sign indicates that the direction is opposite to the initial velocity.

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Answer:

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The thermal efficiency of a power cycle operating in a reversible manner is found to be 50%. Assuming that the same 2 thermal re
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Answer:

Explanation:

The thermal efficiency of a Power cycle \eta = \dfrac{Q_H -Q_c}{Q_H}

where;

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Q_H = Heat \ flow \ from \ higher \ temperature

Q_c = Heat \ flow \ from \ lower \ temperature

0.5 = \dfrac{Q_H -Q_c}{Q_H}

0.5 Q_H = Q_H - Q_c --- (1)

Q_c = 0.5 Q_H         ---- (2)

The coefficient of performance is:

COP_R = \dfrac{Q_c}{Q_H -Q_c}

let replace the value of Q_c = 0.5 Q_H   in the above equation then;

COP_R = \dfrac{0.5Q_H}{Q_H -0.5 Q_H}

COP_R = \dfrac{0.5Q_H}{0.5 Q_H}

COP_R = 1

The

On the other hand,  the heat pump

COP_{HP} = \dfrac{Q_H}{Q_H -Q_c}

By replacing equation (1) into the above equation; we have:

COP_{HP} = \dfrac{Q_H}{0.5Q_{H}}

COP_{HP} = \dfrac{1}{0.5}

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t

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dalvyx [7]
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<h2>Answer: process of converting matter into energy</h2><h2></h2>

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In other words:

<h2>Matter is converted to energy .</h2>

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Answer:

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