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3 years ago

the mass of element Q found in 1.00 mole of each of four compounds is 38.0 grams, 57.0 grams, 76.0 grams and 114 grams.

2 answers:

7 0

The question; The mass of element Q found in 1.00 mole of each of four different compounds is 38.0 grams, 57.0 grams, 76.0 grams, and 114 grams, respectively. A possible atomic weight of Q is;

Answer;

Atomic weight of Q = 19 g

Solution and explanation;

A possible atomic mass of Q has to be a factor of 38, 57, 76, and 114.

Because the number of atoms of Q in any compound must be a whole number.

-Finding a greatest common Divider of 38, 57, 76, and 114

38 = 2(19)

57 = 3(19)

76 = 4(19)

114 = 6(19)

Thus; the greatest common divider is 19

Hence, the possible atomic mass of Q is 19 g

NemiM [27]3 years ago

5 0

Missing question: A possible atomic weight of Q is?

A)12.7.

B)19.0.

C)27.5

D)38.0

E)57.0.

Answer is: possible atomic weight of Q is B) 19.0.

Molecular weight of first molecule is 38.0 g/mol.

Molecular weight of second molecule is 57.0 g/mol.

Molecular weight of third molecule is 76.0 g/mol.

Molecular weight of fourth molecule is 114.0 g/mol.

All four molecular weights can be division only by 19 to get whole number:

Molecule 1 (38 ÷ 19 = 2), molecule 2 (57 ÷ 19 = 3), molecule 3 (76 ÷ 19 = 4) and molecule 4 ( 114 ÷ 19 = 6).

Molecular formulas are than Q₂, Q₃, Q₄ and Q₆.

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Answer:

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Solubility product of $Zn(CH_{3}COO)_{2}$ ( $K_{sp}$ ) is written as- $K_{sp}=[Zn^{2+}][CH_{3}COO^{-}]^{2}$

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3 years ago

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Answer:

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2 years ago

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Answer:

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Explanation:

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