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Harrizon [31]
3 years ago
15

The half-life of caffeine is 5 hours. If you ingested a 30 oz Big Gulp, after how much time will have to pass before you have un

der 1 oz of caffeine remaining?
Physics
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

The time that will have to pass before one has under 1 oz of caffeine remaining is 24.53 hours

Explanation:

Here, we have the formula for half life as follows;

N(t) = N_0(\frac{1}{2})^{\frac{t}{t_{1/2}}

Where:

N(t) = Remaining quantity of the substance = 1 oz

N₀ = Initial quantity of the substance = 30 oz

t = Time duration

t_{1/2} = Half life of the substance = 5 hours

Therefore, plugging in the values, we have

1= 30(\frac{1}{2})^{\frac{t}{5}}

\frac{1}{30} = (\frac{1}{2})^{\frac{t}{5}}\\ln(\frac{1}{30}) =\frac{t}{5} ln(\frac{1}{2})\\\frac{t}{5}  = \frac{ln(\frac{1}{30}) }{ ln(\frac{1}{2})} = 4.91\\ t = 4.91 \times 5 = 24.53 \ hours

The time that will have to pass before one has under 1 oz of caffeine remaining = 24.53 hours.

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ludmilkaskok [199]

Answer:

maximum possible speed by solving above equation for 7D is

v_{max} = \sqrt{\frac{49}{5}gD}

minimum possible value of speed for solving x = 6D is given as

v_{min} = \sqrt{9gD}

Explanation:

Let the nozzle of the hose be at the origin. Then the nearest part of the rim of the tank is at (, ) =  (6, 2) and the furthest part of the rim is at (, ) = (7, 2).

The trajectory of the water can be found as follows:

x = (v_o cos45) t

y =  (v_o sin45) t - \frac{1}{2}gt^2

Now from above two equations we have

y = x - \frac{gx^2}{v_o^2}

now we know that height of the cylinder is 2D so we have

x - \frac{gx^2}{v_o^2} = 2D

by solving above equation we have

x = \frac{v_o^2 \pm v_o^2\sqrt{1 - \frac{8gD}{v_o^2}}}{2g}

now we know that maximum value of x is 7D

so the maximum possible speed by solving above equation for 7D is

v_{max} = \sqrt{\frac{49}{5}gD}

minimum possible value of speed for solving x = 6D is given as

v_{min} = \sqrt{9gD}

6 0
3 years ago
If we increase the distance traveled when doing work , and keep all other factors the same, what will happen?
Dmitriy789 [7]
D.increase the amount of work
5 0
3 years ago
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Luis wants to compare the density of three solid objects that are different shapes and sizes. What information does he need to m
tatyana61 [14]

Answer:

u need to make sure that comparison is = to shapes and then find the shapes sizes and add them

7 0
3 years ago
Find<br>the equevalent unit<br>for Ohm using<br>the<br>geren<br>formula.<br>늘​
Brut [27]

Answer:

V/A

Explanation:

Resistance equals voltage divided by current. You already know resistance's unit is the Ohm. Voltage's unit is the Volt and current's is ths Ampere. Now you can do something like this:

1Ω=\frac{1V}{1A} ⇔

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Hope this helped :)

7 0
3 years ago
Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm
cestrela7 [59]

Answer:

0.043 m

Explanation:

From the attachment, the shaded part is the ethyl alcohol. The crossed part on the other hand, is that of glycerin.

The height of the Ethyl Alcohol is h2 = 0.25 m, it's density is ρ2 = 790 kg/m³. The density of glycerin is ρ1 = 1260 kg/m³

If we assume pressure at the two points to be the same, then

P1 = P2

ρ1.g.V1 = ρ2.g.V2

ρ1.A.h1 = ρ2.A.h2

ρ1.h1 = ρ2.h2, making h1 subject of formula

h1 = ρ2.h2 / ρ1, so that

h1 = 790 * 0.25 / 1260

h1 = 197.5 / 1260

h1 = 0.157 m

Δh = 0.2 - 0.157

Δh = 0.043 m or 4.3 cm

8 0
3 years ago
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